First you simply have to substitute 2 in replace of all the a's, and -2 in replace of all of the b's
4((2)2+2(-2))
Then you want to follow the order of operations, PEMDAS (Parantheses-Exponent-Multiplication-Division-Addition-Subtraction), and multiply within the parantheses.
4(4+(-4))
Next you will add within the parantheses (So add the 4 and -4 together)
4(2² + 2(-2)) - 2(-2) = 4(4-4) + 4 = 4*0 + 4 = 4
Your answer will be 4 hope this helps
The answers 4, hope it helps
4
Step-by-step explanation:
Firstly simplify your brackets...,
; 4(a^2 + 2b) = 4a^2 + 8b...then substitute it onto the bracket
; 4a^2 + 8b - 2b
; 4a^2 + 6b,then substitute with the given values of a and b
; 4(2)^2)+ 6(-2)
; 16 - 12 = 4
First you simply have to substitute 2 in replace of all the a's, and -2 in replace of all of the b's
4((2)2+2(-2))
Then you want to follow the order of operations, PEMDAS (Parantheses-Exponent-Multiplication-Division-Addition-Subtraction), and multiply within the parantheses.
4(4+(-4))
Next you will add within the parantheses (So add the 4 and -4 together)
4(0)
Lastly multiply
0
Your answer is 0
Hope this helps!
4
Step-by-step explanation:
4 ( (2)^2 + 2(-2) ) - 2(-2)
4 ( 4 - 4 ) + 4
0 + 4 = 4