Evaluate 4(a2 + 2b) – 2b when a = 2 and b = –2

Evaluate 4(a2 + 2b) - 2b when a = 2 and b = –2

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  1. 4

    Step-by-step explanation:

    Firstly simplify your brackets...,

    ; 4(a^2 + 2b) = 4a^2 + 8b...then substitute it onto the bracket

    ; 4a^2 + 8b - 2b

    ; 4a^2 + 6b,then substitute with the given values of a and b

    ; 4(2)^2)+ 6(-2)

    ; 16 - 12 = 4

  2. First you simply have to substitute 2 in replace of all the a's, and -2 in replace of all of the b's

    4((2)2+2(-2))

    Then you want to follow the order of operations, PEMDAS (Parantheses-Exponent-Multiplication-Division-Addition-Subtraction), and multiply within the parantheses.

    4(4+(-4))

    Next you will add within the parantheses (So add the 4 and -4 together)

    4(0)

    Lastly multiply

    0

    Your answer is 0

    Hope this helps!

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