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Evaluate each absolute value |-3.7|

Posted on October 23, 2021 By Kiridis03 4 Comments on Evaluate each absolute value |-3.7|

Evaluate each absolute value |-3.7|


[tex]Evaluate each absolute value |-3.7|[/tex]

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Comments (4) on “Evaluate each absolute value |-3.7|”

  1. naomicervero says:
    October 23, 2021 at 2:06 pm

    3.7 is your answer

    Step-by-step explanation:

    because an absolute value is the opposite of an number like -4.8 is 4.8

    Reply
  2. elitehairnerd1964 says:
    October 24, 2021 at 1:11 am

    20 ÷ (5 × 2 - 6) + 8=20:(10-6)+8=20:4+6=5+6=11

    (20 ÷ 5) × 2 – 6 + 8=4*2-6+8=8-6+8=2+8=10

    20 ÷ (5 × 2) – 6 + 8=20:10-6+8=2-6+8=-4+8=4

    (20 ÷ 5) × (2 – 6) + 8=4*(-4)+8=-16+8=-8

    Reply
  3. jameslinimk says:
    October 24, 2021 at 2:21 am

    The code with explanatory comments are given in Python below

    Explanation:

    #2.22

    s = "Lionel Pogba"   #string s with names having LP as initials

    names = s.split()  #splits the string into individual characters

    initial = ""  #we are initialising the initials as an empty string

    for i in names:

       initial += i[0]  #making the initials of the string

    print(initial)

    #2.23

    l = [3, 7, -2, 12]  

    range = (max(l) - min(l))  #declare and initialise variable range for the range

    print(range) #output of the range

    #2.24

    l1 = [3, 7, 17, -2, 12]

    #(a)

    midIndex = int(len(l1)/2)  #evaluates half the length of the list

    #which corresponds to the middle index of the list

    print(midIndex)

    #(b)

    print(l1[midIndex])  #assigns the value of the middle index of the list

    #corresponding to the middle element

    #(c)

    l1.sort(reverse=True) #reverses the elements of the list to descending order

    print(l1)

    #(d)

    firstValue = l1[0]  #firstValue variable representing the first element

    l1 = l1[1:] + [firstValue] #assigning the location to the last position

    print(l1)

    Reply
  4. kingofguns2826 says:
    October 24, 2021 at 7:11 am

    Positive 3.7

    The only time absolute is negative is if the negative is outside absolute value
    |-5|=5
    |5|=5
    -|5|=-5

    Reply

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