# Example: Study the example on the right to help you complete the problem below. Solve the equation A= bh for h. 2 O h Ab 8 = (1/3)6x (3)8 = (3)(1/3)6*

Example: Study the example on the right to help you complete the problem below. Solve the equation A= bh for h. 2 O h Ab 8 = (1/3)6x (3)8 = (3)(1/3)6* multiplication property (3)8 = 6x simplify (3)8/6 = 6x/6 multiplication property (3)8/6 = x simplify simplify and symmetric property h = 2Alb O h = 2b/A he (1 b/A​

## This Post Has 3 Comments

1. jessnolonger says:

Answer : The equation for 'h' is $h=\frac{2A}{b}$

Step-by-step explanation :

The given equation is:

$A=\frac{1}{2}bh$

Now we have to determine the equation for 'h'.

$A=\frac{1}{2}bh$

Multiplying the equation by 2.

$2\times A=2\times \frac{1}{2}\times bh$

on simplifying, we get:

$2\times A=bh$

Dividing the equation by 'b'.

$\frac{2\times A}{b}=\frac{bh}{b}$

$\frac{2\times A}{b}=h$

or,

$h=\frac{2A}{b}$

Therefore, the equation for 'h' is $h=\frac{2A}{b}$

2. hamzzaqasim44 says:

h = $\frac{2A}{b}$

Step-by-step explanation:

Given

A = $\frac{1}{2}$ bh ( multiply both sides by 2 to clear the fraction )

2A = bh ( divide both sides by b )

$\frac{2A}{b}$ = h

3. MickeyAppleX says:

The question is poorly formatted:

Example: Study the example on the right to help you complete the problem below.

Solve the equation

$A= \frac{1}{2}bh$ for h.

Options:

$h = \frac{2A}{b}$    $h = \frac{2b}{A}$      $h = \frac{b}{A}$     $h = 2Ab$​

Example:

$8 = \frac{1}{3}6x$

Multiplication property

$(3)8 = (3)(\frac{1}{3})6x$

$(3)8 = 6x$

Simplify: $(3)\frac{8}{6} = \frac{6x}{6}$

Multiplication property: $(3)\frac{8}{6} = x$

Simplify: $\frac{8}{2} = x$

Simplify : $4 = x$

Symmetric property : $x = 4$

$h = \frac{2A}{b}$

Step-by-step explanation:

Given

$A= \frac{1}{2}bh$

Required

Solve for h

$A= \frac{1}{2}bh$

Multiplication property

$2 * A= \frac{1}{2}bh * 2$

$2A = bh$

Simplify

$\frac{2A}{b} = \frac{bh}{b}$

$\frac{2A}{b} = h$

Symmetric property

$h = \frac{2A}{b}$

Hence, the expression for h is:

$h = \frac{2A}{b}$