# Factor the following expression x^2-36

Factor the following expression x^2-36

## This Post Has 5 Comments

1. ellisc7044 says:

1. C. 4x + 40

2. a. - 2a + 10

3. d. 13x - 45

4. 2c-7d

5. b. -2z - 12

Step-by-step explanation:

1.  4(x+10)  = 4x+4*10 = 4x+40

C

2.  -2(a - 5) = -2*a -2*-5 = -2a+10

A

3.  10x + 3 (x-15)

10x + 3x -3*15

10x+3x-45

13x-45

D

4. -5(c+d) + 7c - 2d

-5c-5d + 7c-2d

-5c+7c -5d -2d

2c-7d

5.  2(2z + 4) - 2 (3z + 10)

2*2z +2*4 -2 *3z -2*10

4z+8 -6z-20

4z-6z+8-20

-2z-12

B

2. CheerA170 says:

Explanation:

the order of evaluation would be represented as

((a + (b * c)1)2 + d)3

a. a * b - 1 + c

b. a * (b - 1) / c mod d

c. (a - b) / c & (d * e / a - 3)

d. -a or c = d and e

e. a > b xor c or d <= 17

f. -a + b

A:

(a) ( ( ( a * b )1 – 1 )2 + c )3

(b) ( ( ( a * ( b – 1 )1 )2 / c )3 mod d )4

(c) ( ( ( a – b )1 / c )2 & ( ( ( d * e )3 / a )4 – 3 )5 )6

(d) ( ( ( – a )1 or ( c = d )2 )3 and e )4

(e) ( ( a > b )1 xor ( c or ( d <= 17 )2 )3 )4

(f) ( – ( a + b )1 )2

3. sara7946 says:

The correct answer is a. Please give me brainlest I hope this helps thanks I appreciate it

4. bklein2020 says:

Factor the following:
x^2 - 36
x^2 - 36 = x^2 - 6^2:
x^2 - 6^2
Factor the difference of two squares. x^2 - 6^2 = (x - 6) (x + 6):
(x - 6) (x + 6)

5. ddmorse2015owug6f says:

Explanation:

a.) * and + has same priority so then: ((a * b) - (1+c))

b.) For (++c++) = ((++c)++) , prefix has high precedence.

In remaining operators * and mod has same precedence So evaluate from left to right. ((a * (b - 1)) / (((++c)++) mod d))

There for order of evaluation: ((a * (b - 1)) / (((++c)++) mod d))

c.) for (d * e / a - 3), * has high priority so ((d *e) / a - 3). Now / and - have same priority so then see association from left to right. so

And & has more priority than / so then order of evaluation: ((a - b) / (c & (((d * e) / a) - 3))

d.) In question d, unary minus(-) has high priority then, - has high priority, then and has high priority and then or has low priority. So then order of evaluation: ((-a) or ((c = d) and e))

e.) Here > and <= has high and same precedence then ( a > b) xor c or (d <= 17)

now xor and or has same priority so associates from left to right.

order of evaluation is : ( ((a > b) xor c) or (d <= 17))

f.) uniary minus(-) has high precedence than + so order of evaluation is : ((-a) + b)

Rewriting the expression where there are no precedence rues and the statement is given right to left associativity:

a. c + 1 - b * a

b. d mod (++c++) / (1 - b) * b

c. (3 - a / e * d) & c / (b - a)

d. e and d = c or -a

e. 17 <= d or c xor b > a

f. b + -a