a.) * and + has same priority so then: ((a * b) - (1+c))
b.) For (++c++) = ((++c)++) , prefix has high precedence.
In remaining operators * and mod has same precedence So evaluate from left to right. ((a * (b - 1)) / (((++c)++) mod d))
There for order of evaluation: ((a * (b - 1)) / (((++c)++) mod d))
c.) for (d * e / a - 3), * has high priority so ((d *e) / a - 3). Now / and - have same priority so then see association from left to right. so
And & has more priority than / so then order of evaluation: ((a - b) / (c & (((d * e) / a) - 3))
d.) In question d, unary minus(-) has high priority then, - has high priority, then and has high priority and then or has low priority. So then order of evaluation: ((-a) or ((c = d) and e))
e.) Here > and <= has high and same precedence then ( a > b) xor c or (d <= 17)
now xor and or has same priority so associates from left to right.
order of evaluation is : ( ((a > b) xor c) or (d <= 17))
f.) uniary minus(-) has high precedence than + so order of evaluation is : ((-a) + b)
Rewriting the expression where there are no precedence rues and the statement is given right to left associativity:
1. C. 4x + 40
2. a. - 2a + 10
3. d. 13x - 45
4. 2c-7d
5. b. -2z - 12
Step-by-step explanation:
1. 4(x+10) = 4x+4*10 = 4x+40
C
2. -2(a - 5) = -2*a -2*-5 = -2a+10
A
3. 10x + 3 (x-15)
10x + 3x -3*15
10x+3x-45
13x-45
D
4. -5(c+d) + 7c - 2d
-5c-5d + 7c-2d
-5c+7c -5d -2d
2c-7d
5. 2(2z + 4) - 2 (3z + 10)
2*2z +2*4 -2 *3z -2*10
4z+8 -6z-20
4z-6z+8-20
-2z-12
B
Explanation:
the order of evaluation would be represented as
((a + (b * c)1)2 + d)3
a. a * b - 1 + c
b. a * (b - 1) / c mod d
c. (a - b) / c & (d * e / a - 3)
d. -a or c = d and e
e. a > b xor c or d <= 17
f. -a + b
A:
(a) ( ( ( a * b )1 – 1 )2 + c )3
(b) ( ( ( a * ( b – 1 )1 )2 / c )3 mod d )4
(c) ( ( ( a – b )1 / c )2 & ( ( ( d * e )3 / a )4 – 3 )5 )6
(d) ( ( ( – a )1 or ( c = d )2 )3 and e )4
(e) ( ( a > b )1 xor ( c or ( d <= 17 )2 )3 )4
(f) ( – ( a + b )1 )2
The correct answer is a. Please give me brainlest I hope this helps thanks I appreciate it
Factor the following:
x^2 - 36
x^2 - 36 = x^2 - 6^2:
x^2 - 6^2
Factor the difference of two squares. x^2 - 6^2 = (x - 6) (x + 6):
(x - 6) (x + 6)
The answers are explained below.
Explanation:
a.) * and + has same priority so then: ((a * b) - (1+c))
b.) For (++c++) = ((++c)++) , prefix has high precedence.
In remaining operators * and mod has same precedence So evaluate from left to right. ((a * (b - 1)) / (((++c)++) mod d))
There for order of evaluation: ((a * (b - 1)) / (((++c)++) mod d))
c.) for (d * e / a - 3), * has high priority so ((d *e) / a - 3). Now / and - have same priority so then see association from left to right. so
And & has more priority than / so then order of evaluation: ((a - b) / (c & (((d * e) / a) - 3))
d.) In question d, unary minus(-) has high priority then, - has high priority, then and has high priority and then or has low priority. So then order of evaluation: ((-a) or ((c = d) and e))
e.) Here > and <= has high and same precedence then ( a > b) xor c or (d <= 17)
now xor and or has same priority so associates from left to right.
order of evaluation is : ( ((a > b) xor c) or (d <= 17))
f.) uniary minus(-) has high precedence than + so order of evaluation is : ((-a) + b)
Rewriting the expression where there are no precedence rues and the statement is given right to left associativity:
a. c + 1 - b * a
b. d mod (++c++) / (1 - b) * b
c. (3 - a / e * d) & c / (b - a)
d. e and d = c or -a
e. 17 <= d or c xor b > a
f. b + -a