4 is the square root of 16, so if it has to be negative, -4 would be the answer. Because you can't find the square root of -16. It could also be +-4 because the square root of -16 is invalid. Hope this helped.
0.777... is rational, because it is a number with infinite but repeating decimal part.1/3 is rational, because it's the division between two integers[tex]-\sqrt{16}=-4[/tex], so this is rational as well.
Since the product of two rational numbers is always rational, we have that
-4
Step-by-step explanation: the square root is 4, so reverse in to negative, and the answer is -4.
= 4 i where i complex number
Step-by-step explanation:
4 is the square root of 16, so if it has to be negative, -4 would be the answer. Because you can't find the square root of -16. It could also be +-4 because the square root of -16 is invalid. Hope this helped.
-4 .
Step-by-step explanation:
Given : [tex]\sqrt{-16}[/tex].
To find : Find the value .
Solution : We have given [tex]\sqrt{-16}[/tex].
We can write the [tex]\sqrt{-16}[/tex] = [tex]\sqrt{- 4 * 4}[/tex].
[tex]\sqrt{-16}[/tex] = -4 .
By the radical rule : [tex]\sqrt{-a *a} =-a[/tex].
Here, a = 4.
So, [tex]\sqrt{-16}[/tex] = -4 .
Therefore, -4 .
The answer is -4. Square root of 16 is 4, so the negative of that is -4.
-13
13
Step-by-step explanation:
Find the square root of the number 169 and use the positive and negative forms.
The positive square root of 169 is 13.
13 x 13 = 169
The negative square root of 169 is -13.
To get the negative square root all you got to do is -√169
To get the positive square root you have to do √169
We can simply observe that.
0.777... is rational, because it is a number with infinite but repeating decimal part.1/3 is rational, because it's the division between two integers[tex]-\sqrt{16}=-4[/tex], so this is rational as well.
Since the product of two rational numbers is always rational, we have that
[tex]0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}[/tex]
are all rationals, since they are the product of two rationals.
On the other hand, we have
[tex]\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}[/tex]
and thus
[tex]3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}[/tex]
which is irrational.
-4 i
Step-by-step explanation:
sqrt(1610) = 40.12 = -40.2
sqrt(680) = 36.08 = -36.08
sqrt(410) = 20.25 = -20.25
sqrt(27) = 5.20 = -5.20
is that supposed to be 025 or negative 25?
the way the question is written
the answer is C & D