4 is the square root of 16, so if it has to be negative, -4 would be the answer. Because you can't find the square root of -16. It could also be +-4 because the square root of -16 is invalid. Hope this helped.

0.777... is rational, because it is a number with infinite but repeating decimal part.1/3 is rational, because it's the division between two integers[tex]-\sqrt{16}=-4[/tex], so this is rational as well.

Since the product of two rational numbers is always rational, we have that

-4

Step-by-step explanation: the square root is 4, so reverse in to negative, and the answer is -4.

= 4 i where i complex number

Step-by-step explanation:

4 is the square root of 16, so if it has to be negative, -4 would be the answer. Because you can't find the square root of -16. It could also be +-4 because the square root of -16 is invalid. Hope this helped.

-4 .

Step-by-step explanation:

Given : [tex]\sqrt{-16}[/tex].

To find : Find the value .

Solution : We have given [tex]\sqrt{-16}[/tex].

We can write the [tex]\sqrt{-16}[/tex] = [tex]\sqrt{- 4 * 4}[/tex].

[tex]\sqrt{-16}[/tex] = -4 .

By the radical rule : [tex]\sqrt{-a *a} =-a[/tex].

Here, a = 4.

So, [tex]\sqrt{-16}[/tex] = -4 .

Therefore, -4 .

The answer is -4. Square root of 16 is 4, so the negative of that is -4.

-13

13

Step-by-step explanation:

Find the square root of the number 169 and use the positive and negative forms.

The positive square root of 169 is 13.

13 x 13 = 169

The negative square root of 169 is -13.

To get the negative square root all you got to do is -√169

To get the positive square root you have to do √169

We can simply observe that.

0.777... is rational, because it is a number with infinite but repeating decimal part.1/3 is rational, because it's the division between two integers[tex]-\sqrt{16}=-4[/tex], so this is rational as well.

Since the product of two rational numbers is always rational, we have that

[tex]0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}[/tex]

are all rationals, since they are the product of two rationals.

On the other hand, we have

[tex]\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}[/tex]

and thus

[tex]3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}[/tex]

which is irrational.

-4 i

Step-by-step explanation:

sqrt(1610) = 40.12 = -40.2

sqrt(680) = 36.08 = -36.08

sqrt(410) = 20.25 = -20.25

sqrt(27) = 5.20 = -5.20

is that supposed to be 025 or negative 25?

the way the question is written

the answer is C & D