Find the area of the triangle

in square inches.

height 110 in.

length 1.5 ft

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Find the area of the triangle

in square inches.

height 110 in.

length 1.5 ft

the answer B

Step-by-step explanation:

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Choose the second answer.yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square.basically, this is true due to the pythagorean theorem.

yes

step-by-step explanation:

The Correct answer is B

Step-by-step explanation:

I took the unit practice test and got a 100%

A. The sum of the areas of the two smaller squares is equal to the area of the larger square.

Step-by-step explanation:

In Figure 1, a, b, and c form the sides of PQR. They also form the sides of square A, square B, and square C respectively.

For a right triangle, the Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Applying the Pythagorean theorem to PQR, it can be seen that a2 + b2 = c2.

Similarly, the following statements will be true for XYZ and STU.

For XYZ, d2 + e2 = f2.

For STU, g2 + h2 = i2.

By observation, along with the Pythagorean theorem, the sum of the areas of the two smaller squares is equal to the area of the larger square.

" B is your best choice but it is very badly stated. this gives an Example of the Pythagorean theorem. it does Not demonstrate it. B is written incorrectly, it should say "sum of squares of the lengths of the legs" Not "sum of the lengths of the two legs of any right angle squared"

they will manufacture 8496 cars

I think it’s C.) and I hope this helped!

the correct answer is B

"yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square."

Step-by-step explanation:

took the test, got it right. nice day folks. amos @kay_flores575

a ) 2 r, b ) A c : A sq = π : 4, c ) The table: Area of the circle: 4 π , 9 π, 16 π, 4 r² π // Length of 1 side of the square: 4, 6, 8, 4 r // Area of the square: 16, 36, 64, 16 r² // Ratio: π/4, π/4, π/4, π/4.

Step-by-step explanation:

a ) The side of the square is twice the radius of the circle.

Therefore 2 r .

b ) A circle : A square = r² π : 4 r² = π : 4 = π / 4 ( or 3.14 : 4 )

c ) The area of the circle: A ( 2 ) = 2² π = 4 π

A ( 3 ) = 3² π = 9 π

A ( 4 ) = 4² π = 16 π

A ( 2 r ) = ( 2 r )² π = 4 r² π

The length of 1 side of the square:

L ( 2 ) = 2 · 2 = 4

L ( 3 ) = 2 · 3 = 6

L ( 4 ) = 2 · 4 = 8

L ( 2 r ) = 2 · 2 r = 4 r

Area of the square: A ( 4 ) = 4² = 16, A ( 6 ) = 6² = 36, A ( 8 ) = 8² = 64, A ( 4 r ) = ( 4 r ) ² = 16 r²

Ratio: 4π : 16 = π/4

9 π : 36 = π/4

16 π : 64 = π/4

4 r² π / 16 r² = π/4

C. The sum of the areas of the two smaller squares is equal to the area of the larger square.

Step-by-step explanation:

9 + 16 = 25

36 + 64 = 100

25 + 144 = 169

The relations "less than" and "greater than" can be ruled out. These observations are consistent with selection C.

The triangle area is half the product of the square roots of the squares on the legs, so the areas of the triangles are (respectively) 6, 24, 30. These are not related to the sum of the smaller squares, so the last selection can also be ruled out.