# Find the equation of the line containing the points (-7, 9) and (7,2).

Find the equation of the line containing the points (-7, 9) and (7,2).

## This Post Has 7 Comments

1. jakester00792 says:

See attachment for math work.

$Find the equation of the line containing the points (-7, 9) and (7,2).$

2. babytony1210 says:

c

Explanation:

3. belen1266 says:

d. nitrogen-containing base .

Explanation:

A nucleotide comprises a phosphate group, a pentose sugar and a nitrogenous base (nitrogen-containing base).

A nitrogenous base is a type of aromatic heterocyclic organic compound which essentially has nitrogen in it. The base can be a purine or pyrimidine. Purine nitrogenous bases are adenine (A) and guanine (G) while pyrimidine nitrogenous bases are cytosine (C), thiamine (T) and uracil (U).

Till the time a base is not attached to covalently linked phosphate group and a pentose sugar, it is known as nucleoside. But as soon as we attach any nitrogenous base to the nucleoside, a nucleotide is formed. So it means a nucleotide is nucleoside + nitrogenous base.

Examples are as under:

A nucleotide which has adenine as nitrogenous base is known as adenosine triphosphate (ATP) while a nucleotide which has guanine as nitrogenous base is known as Guanosine-5'-triphosphate (GTP).

4. hatl says:

y=-1/2x+11/2

Step-by-step explanation:

equation of line is y=mx+b

m=y2-y1/x2-x1

m=2-9/7-(-7)

m=-7/14

m=-1/2

y=-1/2x+b

You can use either (x,y) point you want, the answer will be the same

(-7,9)

y=mx+b or 9=-1/2 × -7+b, or solving for b: b=9-(-1/2)(-7). b=11/2.

(7,2)

y=mx+b or 2=-1/2 × 7+b, or solving for b: b=2-(-1/2)(7). b=11/2.

so then you just put it all together

y=-1/2x+11/2

c

Step-by-step explanation:

i did it

6. Keekee9847 says: