Find the missing factor G that makes the equality true.

18y3 = (G)(2y^2)

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Find the missing factor G that makes the equality true.

18y3 = (G)(2y^2)

21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

i think this is correct

B = 7[tex]x^{4}[/tex]

Step-by-step explanation:

Checking the result of B

- 5x² × 7[tex]x^{4}[/tex] = - 35[tex]x^{2+4}[/tex] = - 35[tex]x^{6}[/tex] ← Correct

[tex]D=-5y^2[/tex]

Step-by-step explanation:

[tex]-15y^4=D(3y^2)\\D=\frac{-15y^4}{3y^2} \\D=-\frac{15}{3}\cdot\frac{y^4}{y^2} \\D=-5y^2[/tex]

21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

B=3y^(2)

Step-by-step explanation:

1225/8

Step-by-step explanation:

1225= 4(2)c

1225=8c divide the 8 to isolate the c

1225/8=c

-6x^2 y^3 = B

Step-by-step explanation:

42x^5y^4=(-7x^3y)(B)

Solve for B

Divide by -7

42x^5y^4/-7=(-7x^3y)(B)/-7

-6 x^5 y^4 = x^3 y B

Divide by x^3

-6 x^5 y^4/x^3 = x^3 y B/x^3

-6 x^5/x^3 y^4 = By

-6 x^2 y^4

Divide by y

-6x^2 y^4/y = By/y

-6x^2 y^3 = B

-4x^2

Step-by-step explanation:

Just did it on khan academy

1.135y

Step-by-step explanation:

Im assuming 21y4 are being multiplied making it 21 x 4 x y

Just divide over 74 to the left side

G= 27/y; y≠0

Step-by-step explanation:

Switch sides

G2y^2=18y·3

Multiply the numbers: 18·3=54

G2y^2=54y

Divide both sides by 2y^2:

G·2y^2/2y^2=54y

or y≠0

Simplify

G= 27/y; y≠0