Find the value of each polygon

Find the sum of the interior angles first

[tex]Find the value of each polygon Find the sum of the interior angles first[/tex]

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Find the value of each polygon

Find the sum of the interior angles first

[tex]Find the value of each polygon Find the sum of the interior angles first[/tex]

here the answers ur welcome also plz mark as brainliest if someone else anwers

hence, the required result is [tex]b-a=\left[\begin{array}{ccc}1& 1& -2\\1& 1& -2\\1& 1& -2\end{array}\right][/tex]

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

[tex]a=\left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right][/tex]

[tex]b=\left[\begin{array}{ccc}2& 3& 1\\5& 6& 4\\8& 9& 7\end{array}\right][/tex]

we have to compute b-a which means subtracting corresponding elements of a from b.

[tex]b=\left[\begin{array}{ccc}2& 3& 1\\5& 6& 4\\8& 9& 7\end{array}\right][/tex]-[tex]a=\left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right][/tex]

[tex]b-a=\left[\begin{array}{ccc}1& 1& -2\\1& 1& -2\\1& 1& -2\end{array}\right][/tex]

the answer to question 1 is -8, 28.

step-by-step explanation:

First subtract 10 from both side

y^2+6y-16=0

(y+8)(y-2)=0

-8 and 2