answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.
u also answered this so i think u would know but i am here to
put in or use mine
[tex]For the figures below, assume they are made of semicircles, quarter circles and squares. for each sh[/tex]
80°
Step-by-step explanation:
x=80°
sides are equal therefore it is an iscocelus triangle
exterior angle =180-50=130°
it is iscoceles therefore base angles are equal and base angles are 50° and 50°
sum of base angles +x°=180°(angle sum)
=>100+x°=180
x°=180-100
=>x°=80°
plzz mark my answer as brainliest
i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer because of that.
step-by-step explanation:
answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.
u also answered this so i think u would know but i am here to
put in or use mine
[tex]For the figures below, assume they are made of semicircles, quarter circles and squares. for each sh[/tex]