Home Mathematics For f(x)=4x+1 and g(x)=x^2-5, find (f/g)(x) For f(x)=4x+1 and g(x)=x^2-5, find (f/g)(x)Mathematics MangustaylorOctober 23, 202110 CommentsFor f(x)=4x+1 and g(x)=x^2-5, find (f/g)(x)
x^2 + 4x - 4.Step-by-step explanation:(f + g)(x) is the same thing f(x) + g(x), which is the same thing as (4x + 1) + (x^2 - 5).(4x + 1) + (x^2 - 5)= x^2 + 4x + 1 - 5= x^2 + 4x - 4Hope this helps!Reply
x^2 +4x -4Step-by-step explanation:f(x) = 4x+1g(x) = x^2-5 (f+g)(x) = 4x+1 + x^2 -5Combine like terms = x^2 +4x +1-5 =x^2 +4x -4Reply
(f + g)(x) is x² + 4x - 4Step-by-step explanation:Step 1:Given f(x) = 4x + 1, g(x) = x² - 5. Find (f+g)(x)(f + g)(x) = f(x) + g(x) = 4x + 1 + x² - 5 = x² + 4x - 4Reply
The answer is A, x^2 + 4x - 4Just did this in calculus last year. It's really simple, you just add them together.(f+g)(x)x^2 - 5 + 4x + 1x^2 + 4x - 4Good luck!Reply
x^2 + 4x - 4.
Step-by-step explanation:
(f + g)(x) is the same thing f(x) + g(x), which is the same thing as (4x + 1) + (x^2 - 5).
(4x + 1) + (x^2 - 5)
= x^2 + 4x + 1 - 5
= x^2 + 4x - 4
Hope this helps!
i hope this helps !
[tex]For f(x)=4x+1 and g(x)=x^2-5, find (f•g)(x) Im stuck please help[/tex]
4X³+x²-20x-5
Step-by-step explanation:
(f•g)(x)=(4x+1)•(x²-5)=4x³-20x+x²-5
answer:
00
step-by-step explanation:
Step-by-step explanation:
(f+g)(x) = f(x) + g(x)
= 4x + 1 + x² - 5
= x² + 4x - 4
x^2 +4x -4
Step-by-step explanation:
f(x) = 4x+1
g(x) = x^2-5
(f+g)(x) = 4x+1 + x^2 -5
Combine like terms
= x^2 +4x +1-5
=x^2 +4x -4
(f + g)(x) is x² + 4x - 4
Step-by-step explanation:
Step 1:
Given f(x) = 4x + 1, g(x) = x² - 5. Find (f+g)(x)
(f + g)(x) = f(x) + g(x) = 4x + 1 + x² - 5 = x² + 4x - 4
The answer is A, x^2 + 4x - 4
Just did this in calculus last year. It's really simple, you just add them together.
(f+g)(x)
x^2 - 5 + 4x + 1
x^2 + 4x - 4
Good luck!
4(x^2-5)+1 --> the answer is 4x^2 - 19
answer is a
Step-by-step explanation: