For the reaction 2 H2(g) + O2(g) → 2 H2O(g), how many liters of water can be made from 5.0 L of oxygen gas and an excess of hydrogen?
For the reaction 2 H2(g) + O2(g) → 2 H2O(g), how many liters of water can be made from 5.0 L of oxygen gas and an excess of hydrogen?
5L O2 x 1 mol O2/ 22.4L O2 x 2 mol H20/ 1 mol O2 x 22.4L H20/ 1 mol H20 = 10 L H2O
Explanation:
For future reference though, since its at STP that means that the coefficient are in proportion. Since oxygen has a coefficient of 1 and water has a coefficient of 2 for every 1 liter of oxygen there is 2 liters of water. Hence you started with 5 liters and ended with 10
2fe + 3h2so4 -> fe2(so4)3 + 3h2
it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.
you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.
we change the coefficients instead as that only changes the number of molecules rather than the substance itself.
hope this !
space exploration has led to the development and technological improvement of many everyday items. (if this answer is wrong i will find the right answer) : )