For two events, m and n, p(m)=0.7, p(n|m)=0.3, and p(m’|n’)

Comments (3) on “For two events, m and n, p(m)=0.7, p(n|m)=0.3, and p(m’|n’)”

1. step-by-step explanation:

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2. a

   step-by-step explanation:

   [tex]Can you me with these three questions?[/tex]

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3. Topic:Conditional Probability

   For any two events A and B, where P(B) ≠ 0, P( A | B ) = P( A ∩ B ) / P( B ) = P( B | A) * P(A) / P(B)..i.e..{the probability of A given B is equal to the probability of A and B divided by the probability of B}

   For a set of events A1, A2, A3, ... , An,
   hence,
   P(B) 
   = P(B and A1) + P(B and A2) + ... + P(B and An) 
   = P(B | A1) * P(A1) + P(B | A2) * P(A2) + ... + P(B | An) * P(An)

   P(M | N) 
   = P(N | M) * P(M) / P(N) 
   = P(N | M) * P(M) / (P(N | M) * P(M) + P(N | M') * (1 - P(M))) 
   Substitute Values you get ?

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