Given the equation 6x – 2y = 18 in standard form. Show how you would convert the equation into slope-intercept

Given the equation 6x - 2y = 18 in standard form. Show how you would convert the equation into slope-intercept form → y = mx + b. You must show your work to receive full credit. (3 points)

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  1. A standard form equation is when it is set up

    Ax + By = C.

    6x + 2y = 4

    A slope-intercept form equation is when it is set up y=mx+b.

    Y = - 3x + 2

    In order to go from one form to another, all you have to do is change the order of the given numbers.  First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it.  At this point your equation will be set up By = -Ax + C.  Then you want to divide the B from the By and the rest of the equation.  Therefore you will have y = - Ax/B + C/B.  This is the same thing as the slope-intercept form, just a few of the letters are different.

    Example 1:        

    Change from standard to slope form

    8x + 4y = 16

    8x + 4y = 16  first subtract  8x

    4y = -8x + 16   then divide all by 4

    y = -2x + 4   slope form

    Example 2:

     6x + 3y = 21

    6x + 3y = 21  subtract  6x

    3y = -6x + 21  then divide all by 3

    y = -2x + 7   slope form

    pls mark brainest

  2. Answer y = 3x-9

    Step-by-step explanation:

    This is the expression

    [tex]6x-2y=18[/tex]

    This is what we want to convert to

    [tex]y =mx+b[/tex]

    We plug the values into the formula.

    [tex]-2y=-6x+18[/tex]

    Divide by -2 to get rid of -2 in front of y

    [tex]\frac{-2y=-6x+18}{-2}[/tex]

    Solve where possible

    [tex]y = \frac{-6}{-2}x+\frac{18}{-2}[/tex]

    Result

    [tex]y = 3x-9[/tex]

  3. An equation using the slope-intercept form would be y=mx+b. M would be the slope and b would be the intercept. For example, if slope:5 and intercept:6 the equation would be y=5x+6. Hope I helped!

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