Given the function y=x^2-3/x^2+5x+6 choose th correct horizontal asymptote. none y=0 y=1 y=-2, y=-3

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Given the function y=x^2-3/x^2+5x+6 choose th correct horizontal asymptote. none y=0 y=1 y=-2, y=-3

y = 1

Step-by-step explanation:

Given function is:

[tex]\frac{x^2+8x+3}{x^2+3x+1}[/tex]

In order to find the horizontal asymptote, the coefficients of highest degree variable of numerator and denominator are divided.

In our case,

both the numerator and denominator have 1 as he co-efficient of x^2

So the horizontal asymptote is y = 1/1

Hence, third option y=1 s correct ..

NONE

Step-by-step explanation:

Consider that m is the degree of the numerator and n is the degree of the denominator.

The rules for horizontal asymptote (H.A.) are as follows:

If m > n then no H.A. (use long division to find the slant asymptote)

If m = n then H.A. is y = leading coefficient of numerator/leading coefficient of denominator

If m < n then H.A. is y = 0

Given: g(x) = 5x⁵/(x³ - 2x + 1)

--> m = 5, n = 3

Since m > n then there is no H.A.

is there a picture with this

I’m almost positive it’s the second one but check to be sure