This Post Has 4 Comments

1. y = 1

   Step-by-step explanation:

   Given function is:

   [tex]\frac{x^2+8x+3}{x^2+3x+1}[/tex]

   In order to find the horizontal asymptote, the coefficients of highest degree variable of numerator and denominator are divided.

   In our case,

   both the numerator and denominator have 1 as he co-efficient of x^2

   So the horizontal asymptote is y = 1/1

   Hence, third option y=1 s correct ..

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2.  NONE

   Step-by-step explanation:

   Consider that m is the degree of the numerator and n is the degree of the denominator.

   The rules for horizontal asymptote (H.A.) are as follows:

   If m > n   then no H.A. (use long division to find the slant asymptote)

   If m = n   then H.A. is y = leading coefficient of numerator/leading coefficient of denominator

   If m < n   then H.A. is y = 0

   Given: g(x) = 5x⁵/(x³ - 2x + 1)

   --> m = 5, n = 3

   Since m > n then there is no H.A.

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3. is there a picture with this

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4. I’m almost positive it’s the second one but check to be sure

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