Given the venn diagram below, if a student is randomly selected, what is the probability that he or she is attending both colleges?

[tex]Given the venn diagram below, if a student is randomly selected, what is the probability that he or[/tex]

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Given the venn diagram below, if a student is randomly selected, what is the probability that he or she is attending both colleges?

[tex]Given the venn diagram below, if a student is randomly selected, what is the probability that he or[/tex]

I’m pretty sure 86%,C

Step-by-step explanation:

Add up all the numbers provided (64+28+52+56)=200.

Then divide 28 by 200 this is 14. After, subtract 100%-14%, therefore you get 86%

APEX is 28% vgfgjyjkiijujjkuyhn

Add up all the values shown:

64+28+52+56 = 200

This result indicates that there are 200 students total.

Of these 200 total people, there are 28 who are attending both colleges. This is the value shown in the overlapping region of the two circles.

Divide the two values (28 and 200) to get...

28/200 = 0.14 = 14%

The probability as a decimal value is 0.14 which is saying there's a 14% chance of picking someone who goes to both colleges.

Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Number of people attended Texas only = 64

Number of people attended Binn = 52

Number of people attended both = 28

Number of people not attending any colleges = 56

Total number of people = 64+52+28+56 = 200

Probability of people attending both is given by

[tex]\dfrac{28}{200}\times 100\\\\=14\%[/tex]

So, Probability of people not attending both colleges is given by

[tex]100\%-14\%\\\\=86\%[/tex]

Hence, Option 'C' is correct.