Helps me solve this problem please

[tex]Helps me solve this problem please[/tex]

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Helps me solve this problem please

[tex]Helps me solve this problem please[/tex]

1, 3, 5, 6

Step-by-step explanation: There cannot be the same x value for more than 1 y value.

[tex]x=-2[/tex] or [tex]x=-5[/tex]

step-by-step explanation:

we need to solve for 'x' the following equation: [tex]\sqrt{(x+6)} - 4 = x[/tex]

we have that:

[tex]\sqrt{(x+6)} - 4 = x[/tex] ⇒ [tex](x+6) = (x+4)^{2}[/tex]

⇒ [tex]x+6 = x^{2} + 8x + 16[/tex] ⇒ [tex]x^{2} + 7x + 10 = 0[/tex]

factorizing, we get that:

[tex]x^{2} + 7x + 10 = 0[/tex] ⇒ [tex](x+2)(x+5)=0[/tex]

then, the solutions are: [tex]x=-2[/tex] or [tex]x=-5[/tex]

nothing extraneous has been found!

Hope this will