# Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colaboración. Muchas gracias.

Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colaboración. Muchas gracias.

$Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colabo$

## This Post Has 4 Comments

1. Expert says:

the answer is 0.42 is that is an option. this question provides no info

2. Expert says:

(no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.

3. Expert says:

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4. Expert says:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally