Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colaboración. Muchas gracias.

Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colaboración. Muchas gracias.


[tex]Holaa a todos, vengo a pedirles que me colaboren en este ejercicio, agradezco de antemano su colabo[/tex]

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  1. (no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.

  2. percent abundance for cu-63 can be shown as:

    63 x + 65 (1-x) = 62.9296

    65 - 62.9296 = 2 x

    x = 1.035

    thus, percent abundance for cu-63 is 1.035

    percent abundance for cu-65 can be shown as:

    63 x + 65 (1-x) = 64.9278

    65 - 64.9278 = 2 x

    x = 0.0361

    thus, percent abundance for cu-63 is 0.0361

    the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

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