# Hour: 134 Date: 3 10130Geometry – Law of Sines and Cosines Quiz Reviewc = a + b2 – 2abcos C C=cos- c-aʻ- b’ sin A sin B sin-2ab

Hour: 134 Date: 3 10130
Geometry - Law of Sines and Cosines Quiz Review
c = a + b2 - 2abcos C C=cos- c-aʻ- b' sin A sin B sin
-2ab a b c
Use the Law of Cosines to solve problems #1 & 2. You must show all work for credit.
1. Find side AB
5
78°​

## This Post Has 4 Comments

1. NeverEndingCycle says:

Sinθ=opposite side/hypotenuse
where both the sides are relative to theta.

in this case, 22 is your hypotenuse. theta (θ) is the angle you are examining. i've included a diagram for reference because the equations may format differently depending on which angle you choose as theta.

using my diagram:

sinθ = o/h
sin 15 = o/22
sin 15(22) = o
o=5.69m/s

therefore the vertical component is about 5.69m/s.

cosθ=a/h
cos15 = a/22
cos15(22) = a
a = 21.25m/s


$Atrain goes up a hill with a 15º incline. if the train has constant speed of 22 m/s, what are the ve$

Sinθ=opposite side/hypotenuse
where both the sides are relative to theta.

in this case, 22 is your hypotenuse. theta (θ) is the angle you are examining. i've included a diagram for reference because the equations may format differently depending on which angle you choose as theta.

using my diagram:

sinθ = o/h
sin 15 = o/22
sin 15(22) = o
o=5.69m/s

therefore the vertical component is about 5.69m/s.

cosθ=a/h
cos15 = a/22
cos15(22) = a
a = 21.25m/s