How many hydrogen atoms are contained in 167 grams of propane?

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How many hydrogen atoms are contained in 167 grams of propane?

Propane is C3H8

So Molar mass propane = 3*12 + 8*1 = 44

No. of moles of propane = 167/44 = 3.795 moles

From the stoichiometry:

No. of moles of hydrogen = 3.795 moles * (8 moles hydrogen / 1 mole propane) = 30.36 moles

Using Avogadros number, 1 mole of any substance contains 6.022 x 10^23 atoms, therefore:

No. of hydrogen atoms = 30.36 * 6.022 x 10^23 = 1.828 x 10^25 atoms

po-215 i got it right on the quiz

hloride, what is the mass of calcium in

explanation:

9.03 X [tex]10^{22}[/tex] molecules of butane is present in 9.213 grams of the sample.

1.5 atoms of hydrogen are present in the sample 9.123 grams of butane.

Explanation:

Data given:

mass of butane C4H10= 9.123 grams

atomic mass of butane = 58.12 grams/mole

number of molecules =?

number of hydrogen atoms in the sample=?

number of moles is calculated as :

number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]

putting the values in the above equation:

number of moles of butane = [tex]\frac{9.213}{58.12}[/tex]

= 0.15 moles

number of molecules = number of moles x 6.02 x [tex]10^{23}[/tex] (Avagadro number)

Putting the values in above formula:

number of molecules of Butane = 0.15 X 6.023 X [tex]10^{23}[/tex]

= 9.03 X [tex]10^{22}[/tex] molecules

Number of hydrogen atoms:

1 mole of C4H10 contains 10 atoms of H

0.15 moles of C4H10 will have x moles

[tex]\frac{10}{1}[/tex] = [tex]\frac{x}{0.15}[/tex]

x = 0.15 atoms of hydrogen