How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted? f 0.033 mol h2 g 0.099 mol h2 h 0.066 mol h2 j 0.022 mol h2
How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted? f 0.033 mol h2 g 0.099 mol h2 h 0.066 mol h2 j 0.022 mol h2
2Na(s) + 2H₂O(l) = 2NaOH(aq) + H₂(g)
n(NaOH)=0.066 mol
n(H₂)=n(NaOH)/2
n(H₂)=0.066/2=0.033 mol
0.033 mol
Answer : The number of moles of hydrogen gas is, 0.033 mole
Explanation : Given,
Moles of sodium = 0.066 mole
The balanced chemical reaction will be,
[tex]2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq)+H_2(g)[/tex]
From the balanced chemical reaction, we conclude that 2 moles of sodium react with 2 moles of water to give 2 moles of sodium hydroxide and 1 mole of hydrogen has as a product.
As, 2 moles of sodium react to give 1 mole of hydrogen gas
So, 0.066 mole of sodium react to give [tex]\frac{1}{2}\times 0.066=0.033[/tex] moles of hydrogen gas
Therefore, the number of moles of hydrogen gas is, 0.033 mole
Base on my research the complete reaction of hydrogen and sodium are form by this equation 2Na + 2H2O = 2NaOH +H2 If we base from this equation it shows you already the ratio of the moles of the product and reactants taking part in the reaction
1 mole of Na r/w 1 mole of water to produce .5 mole of Hydrogen
Therefore, .066 mole of Na produces .033 moles of H2