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  1. < xcy ≅ < xby

    step-by-step explanation:

    in δcax and δbax,

    ac ≅ ab (given)< cax ≅ < bax   (given)ax ≅ ax (common side)

    so, δcax ≅ δbax (side-angle-side or sas)

    since δcax ≅ δbax, we can conclude < acx ≅ < abx

    in δacy and δaby,

    ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)

    so, δacy ≅ δaby (side-angle-side or sas)

    since δacy ≅ δaby, we can conclude < acy ≅ < aby

    now,

    < acy ≅ < aby

    => < acx + < xcy ≅ < abx + < xby

    => < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

    subtracting < acx from both sides, we get

    < acx + < xcy -< acx ≅ < acx + < xby -< acx

    cancelling out < acx and -< acx from both sides, we get

    < xcy ≅ < xby (proved)

    [tex]Use a paragraph, flow chart, or two-column proof to prove the angle congruency. given: ∠cxy ≅ ∠bxy[/tex]

  2.  It depends what type of equation you are trying to solve for. 
    For slope intercept form (y=mx+b)
     - pick two coordinates and find the slope using the slope formula; y2-y1 over x2-x1. 
    - the y-intercept is usually found in (0, b) form. 
    After you have found the slope and the y - intercept you can finally plug in your numbers to match the formula. 
    Here is an example:
    - My two coordinates on the line are (0,8) and (-1,5) 
    - 8-5 over 0--1 = 3 over 1, or 3 is my slope.
    - To find the y intercept look for the pair that is found in (0,b) form which in this case is (0,8) so my y intercept is 8.
    You found your slope and y intercept so your equation is y = 3x + 8 
    Hopefully this helped! This is how you find an equation for slope intercept form! If it is any other formula it is basically the same general steps. 

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