i known the answer, i just need help with showing the work, i need to show how i found the scale favor and what it was before it was simplified. plz help
[tex]i known the answer, i just need help with showing the work, i need to show how i found the scale fa[/tex]
Step-by-step explanation:
x + 3y + 2z = 7
2x − y + z = 9
-x + 4y + 5z = 14
First add the first and third equations to eliminate x.
7y + 7z = 21
Simplify:
y + z = 3
Solve for y:
y = 3 − z
Substitute into the first two equations:
x + 3(3 − z) + 2z = 7
2x − (3 − z) + z = 9
Simplify:
x + 9 − 3z + 2z = 7 → x − z = -2
2x − 3 + z + z = 9 → 2x + 2z = 12 → x + z = 6
Add the equations to eliminate z.
2x = 4
x = 2
Therefore, z = 4 and y = -1.
Yes. By SAS (side angle side)
Step-by-step explanation:
Just use photomath that’s easier
Dvcxxxdccvfggeveff dc gf
see explanation
Step-by-step explanation:
Given
[tex]\sqrt{\frac{4x^2}{3y} }[/tex]
= [tex]\frac{\sqrt{4x^2} }{\sqrt{3y} }[/tex]
= [tex]\frac{2x}{\sqrt{3y} }[/tex]
Rationalise the denominator by multiplying the numerator/ denominator by [tex]\sqrt{3y}[/tex]
Note that [tex]\sqrt{a}[/tex] × [tex]\sqrt{a}[/tex] = a
= [tex]\frac{2x}{\sqrt{3y} }[/tex] × [tex]\frac{\sqrt{3y} }{\sqrt{3y} }[/tex]
= [tex]\frac{2x\sqrt{3y} }{3y}[/tex]