i known the answer, i just need help with showing the work, i need to show how i found the scale favor and what it was before it was simplified. plz help

[tex]i known the answer, i just need help with showing the work, i need to show how i found the scale fa[/tex]

Step-by-step explanation:

x + 3y + 2z = 7

2x − y + z = 9

-x + 4y + 5z = 14

First add the first and third equations to eliminate x.

7y + 7z = 21

Simplify:

y + z = 3

Solve for y:

y = 3 − z

Substitute into the first two equations:

x + 3(3 − z) + 2z = 7

2x − (3 − z) + z = 9

Simplify:

x + 9 − 3z + 2z = 7 → x − z = -2

2x − 3 + z + z = 9 → 2x + 2z = 12 → x + z = 6

Add the equations to eliminate z.

2x = 4

x = 2

Therefore, z = 4 and y = -1.

Yes. By SAS (side angle side)

Step-by-step explanation:

Just use photomath that’s easier

Dvcxxxdccvfggeveff dc gf

see explanation

Step-by-step explanation:

Given

[tex]\sqrt{\frac{4x^2}{3y} }[/tex]

= [tex]\frac{\sqrt{4x^2} }{\sqrt{3y} }[/tex]

= [tex]\frac{2x}{\sqrt{3y} }[/tex]

Rationalise the denominator by multiplying the numerator/ denominator by [tex]\sqrt{3y}[/tex]

Note that [tex]\sqrt{a}[/tex] × [tex]\sqrt{a}[/tex] = a

= [tex]\frac{2x}{\sqrt{3y} }[/tex] × [tex]\frac{\sqrt{3y} }{\sqrt{3y} }[/tex]

= [tex]\frac{2x\sqrt{3y} }{3y}[/tex]