I need help finding these answers TWT

[tex]I need help finding these answers TWT[/tex]

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I need help finding these answers TWT

[tex]I need help finding these answers TWT[/tex]

Answerthe simplified expression is[tex]2x + 28[/tex]explanationthe given expression is,[tex]2(10) + 2(x - - 4)[/tex]let us deal with the bracket first.the two negatives in the parenthesis will become positive.the expression now becomes,[tex]2(10) + 2(x + 4)[/tex]we now expand the parenthesis to get,[tex]20 + 2x + 8[/tex]we group like terms to obtain,[tex]2x + 8 + 20[/tex]this simplifies to,[tex]2x + 28[/tex]

I hope this helps you

56+35+CB=180

CB=91

AE=117

AEC=180+56=236

BDA=89+56+180=325

Every time we have a transversal crossing parallel lines we get eight angles. Each is either congruent or supplementary to any of the other seven, there are only two angle measures in play.

Here we have two transversals, so each has two angle measures. That doesn't count where the two transversals cross; we'll do those last.

On line a we see a 39° angle. Let's do that first.

39°: ∠13 ∠6 ∠5

It's supplement is 180°-39°=141°

141°: ∠14 ∠12 ∠7 ∠4

Line b has a 74° angle

74°: ∠3 ∠15 ∠18

Supplement:

106°: ∠1 ∠2 ∠16 ∠17

OK, now the middle crossing

∠3 + ∠6 + ∠9 = 180°

74° + 39° + ∠9 = 180°

∠9 = 180° - 74° - 39°

∠9 - ∠11 = 67°

∠8 = ∠10 = 180° - 67° = 113°

spanish?

Step-by-step explanation:

the answer is 99.

PLEASE HELP

Two blocks are arranged as shown below and released from rest. The blocks have masses, m1 = 1.50 kg and 2 = 1.25 kg. The coefficient of kinetic friction between block 1 and the table is 0.211.

(A)What is the acceleration of the blocks?

(B)What is the tension in the string?

(C )Although you are not required to do so, you should be able to continue this problem to find the time required for 2 to reach the floor and the velocity of the system just before reaching the floor. What additional information would you need to find these two quantities? The problem solution will include the calculation of the set quantities so you can check to see if you are correct.

regular Hexagons have angles of 120 degrees

if angle GHE= 90 degrees, angle GEH=60 degrees since its half of 120

since triangles add up to 180,

180-90=90

90-60=30

so question 2 is 30 degrees

question 3 is 60 degrees