Your answer would be ahere is how: perimeter is how long all the sides are. in a rectangle, there are two sets of parallel sides. so, to find this, we would to the following.(15x2)+(4x2)30+838if you have questions ask! and mark me brainliest! i really wanna level up : 3
Your answer would be ahere is how: perimeter is how long all the sides are. in a rectangle, there are two sets of parallel sides. so, to find this, we would to the following.(15x2)+(4x2)30+838if you have questions ask! and mark me brainliest! i really wanna level up : 3
A. (0, 1) and (2, -2)
B. Slope (m) = -³/2
C. y + 2 = -³/2(x - 2)
D. [tex]y = -\frac{3}{2}x + 1[/tex]
E. [tex]\frac{3}{2}x + y = 1[/tex]
Step-by-step explanation:
A. Two points on the line from the graph are: (0, 1) and (2, -2)
B. The slope can be calculated using two points, (0, 1) and (2, -2):
[tex]slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - 1}{2 - 0} = \frac{-3}{2} = -\frac{3}{2}[/tex]
Slope (m) = -³/2
C. Equation in point-slope form is represented as y - b = m(x - a). Where,
(a, b) = any point on the graph.
m = slope.
Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).
Thus:
y - (-2) = -³/2(x - 2)
y + 2 = -³/2(x - 2)
D. Equation in slope-intercept form, can be written as y = mx + b.
Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.
y + 2 = -³/2(x - 2)
2(y + 2) = -3(x - 2)
2y + 4 = -3x + 6
2y = -3x + 6 - 4
2y = -3x + 2
y = -3x/2 + 2/2
[tex]y = -\frac{3}{2}x + 1[/tex]
E. Convert the equation in (D) to standard form:
[tex]y = -\frac{3}{2}x + 1[/tex]
[tex]\frac{3}{2}x + y = 1[/tex]
connie < felicia < stew
step-by-step explanation:
stew:
we need to find the slope
m = (y2-y1)/ (x2-x1)
= (2650-795)/(10-3)
= 1855/7
265 words per minute
connie:
we need to find the slope
m = (y2-y1)/ (x2-x1)
we have two points (0,0) and (4,800)
m = (800-0)/(4-0)
m = 800/4
200 words per minute
felicia:
260 words per minute
200< 260 < 265
connie < felicia < stew
[tex]Need 45 ! compare the rates at which each of the three students read: which student read at a fa[/tex]