If a box with a square cross section is to be sent by a delivery service, there are restrictions on its size such that its volume

If a box with a square cross section is to be sent by a delivery service, there are restrictions on its size such that its volume is given by V=x^2(81-3x) where x is the length of each side of the cross section in inches. A. Is V a function of x?
B. If V=V(x) , find V(14) and V(25)
C. What restrictions must be placed on x so that the problem makes physical sense

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  1. so she walks 3.5 mph, miles per hour, that's her walking speed rate.

    so in 6 hours, she walked

    3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    namely 6(3.5) miles in 6 hours.

    she did that for 3 weeks, so she did it 3 times, 3 times that much is 6(3.5)+6(3.5)+6(3.5), or 3[ 6(3.5) ].

    well, her regular speed is 3.5, so one-half her regular speed will be 3.5/2.

    we know she walked one week for 4 hours at half her speed, that means she walked

    3.5/2 miles

    + 3.5/2 miles

    + 3.5/2 miles

    + 3.5/2 miles

    namely [tex]\bf 4\left[\frac{3.5}{2} \right][/tex].

    [tex]\bf \stackrel{\textit{3 weeks at regular speed for 6 hours}}{3[~~6~(3.5)~~]}~~+~~\stackrel{\textit{one week for 4 hours at half-speed}}{1~~\left[ 4~\left(\frac{3.5}{2} \right) \right]}\\\\\\63~~+~~7\implies 70[/tex]

  2. so she walks 3.5 mph, miles per hour, that's her walking speed rate.

    so in 6 hours, she walked

    3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    + 3.5 miles

    namely 6(3.5) miles in 6 hours.

    she did that for 3 weeks, so she did it 3 times, 3 times that much is 6(3.5)+6(3.5)+6(3.5), or 3[ 6(3.5) ].

    well, her regular speed is 3.5, so one-half her regular speed will be 3.5/2.

    we know she walked one week for 4 hours at half her speed, that means she walked

    3.5/2 miles

    + 3.5/2 miles

    + 3.5/2 miles

    + 3.5/2 miles

    namely [tex]\bf 4\left[\frac{3.5}{2} \right][/tex].

    [tex]\bf \stackrel{\textit{3 weeks at regular speed for 6 hours}}{3[~~6~(3.5)~~]}~~+~~\stackrel{\textit{one week for 4 hours at half-speed}}{1~~\left[ 4~\left(\frac{3.5}{2} \right) \right]}\\\\\\63~~+~~7\implies 70[/tex]

  3. Step-by-step explanation:

    you gotta find out what the number of the suplement is and then multiply that by two and then youll get your answer

  4. The angle is 120 degrees.

    Step-by-step explanation:

    Supplementary angles add up to 180 degrees.

    So if our angle is x it's supplement is 180 - x.

    So we have the equation:

    x = 2(180 - x)

    x = 360 - 2x

    3x = 360

    x = 120 (answer).

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