If a = 6l^2 is the total area of the surface of a cube with sides l length and A = 6 (2l)^2 is that area with 2l sides, then we take the ratio A/a = 6 (2l)^2/(6 l^2) = (2l)^2/l^2 = 4l^2/l^2 = 4. So that A = 4a. And that explicitly shows that the area A with 2l for sides is 4 X a, where a is the area when l is the side length.
Using ratios to compare values of the same thing is the smart way to solve this kind of problem, because many of the values, like the 6 in both, cancel out. In fact, because we found that A/a = (2l/l)^2 we say in general that the area of a cube varies with the square of the length of its side.
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step-by-step explanation:
3. A cube with sides 4 m in length has a volume of 64 m². If each sideof the cube is doubled in length, what is the ratio of the new volume
to the old volume?
a 5:1
b 2:1
C 8.1
Explanation:
If you double each side the volume is 8 times
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If a = 6l^2 is the total area of the surface of a cube with sides l length and A = 6 (2l)^2 is that area with 2l sides, then we take the ratio A/a = 6 (2l)^2/(6 l^2) = (2l)^2/l^2 = 4l^2/l^2 = 4. So that A = 4a. And that explicitly shows that the area A with 2l for sides is 4 X a, where a is the area when l is the side length.
Using ratios to compare values of the same thing is the smart way to solve this kind of problem, because many of the values, like the 6 in both, cancel out. In fact, because we found that A/a = (2l/l)^2 we say in general that the area of a cube varies with the square of the length of its side.
I hope my answer has come to your help. Thank you for posting your question here in We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Dis the solution here
[tex]Final question tell me when your ready all ill post a 100 point question but it will be like how are[/tex]
= √( l²+b²+h²)
=√(12² + 9² + 8² )
=√( 144+81+64)
=√(289)
=17
Hence, longest rod that can be placed in a room of dimensions 12m x 9m x 8m is 17 m
Step-by-step explanation: