If I contain 3 moles of a gas in a container with a volume of 60 liters and a temperature of 400K, what is the pressure inside the container?

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If I contain 3 moles of a gas in a container with a volume of 60 liters and a temperature of 400K, what is the pressure inside the container?

I think its number 5

Answer is in a ph[tex]^{}[/tex]oto. I can't attach it he[tex]^{}[/tex]re, but I uploaded it to a fi[tex]^{}[/tex]le hosting. link below! Good Luck!

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the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.

Answer is in a photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinylnk.cf/rW5p

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

[tex]1.66\cdot 10^5 Pa[/tex]

Explanation:

The ideal gas equation states that:

[tex]pV=nRT[/tex]

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

[tex]n = 3 mol[/tex] (number of moles)

[tex]V=60 L=60\cdot 10^{-3} m^3[/tex] (gas volume)

[tex]T=400 K[/tex]

So we can solve the formula for p, the pressure of the gas:

[tex]p=\frac{nRT}{V}=\frac{(3 mol)(8.314 J/mol K)(400 K)}{60\cdot 10^{-3} m^3}=1.66\cdot 10^5 Pa[/tex]

1.64 atm

PV = nRT —> P = nRT / V

n = 3 moles

R = 0.08206 L atm / mol K

T = 400 K

V = 60 L

P = (3)(0.08206)(400) / 60 = 1.64 atm