# If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in.,

If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in., what must the hight (h) of the frame be?

## This Post Has 5 Comments

1. jujurocks10 says:

You would form this inequality:

52 + 2x < (or equal to) 180

Then, solve as you would in an ordinary equation.

Subtract 52 from both sides of the sign. 180 - 52 = 128.

So, 2x is less than or equal to 128.
Divide 128 into two to get 64.

The height of the frame must be 64 inches.

2. malikbryant2002 says:

First since the perimeter of this problem is P=2b x 2h I first multiplied 26 by 2 and got 52 inches. then I subtracted 52 from 180 and got 128. From there I divide 128 by 2 and I got 64 for the length

3. hjamileth77 says:

The height must be less than 64in.

Step-by-step explanation:

The formula for the perimeter of a rectangle is:

P=2*W+2*H

Where

P : Perimeter

W: Width

H: Length

So the for a perimeter less the 180in.

180>2*26+2*H

180>52+2H

180-52>2H

128>2H

H<64

So the height must be less than 64in.

4. noahdavis8114 says:

Most of the information's required for solving this question is already given. Let us first write them down and then go for finding the answer.
Perimeter of a rectangular picture frame < 180 inches
Width of the rectangular frame = 26 inches
Let us assume the height of the frame = h
Then
2(width + height) < 180
2(26 + h) < 180
52 + 2h < 180
2h < 180 - 52
2h < 128
h < 64
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

5. KaleahV says:

If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in., what must the height h of the frame be?