If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in., what must the hight (h) of the frame be?

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If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in., what must the hight (h) of the frame be?

You would form this inequality:

52 + 2x < (or equal to) 180

Then, solve as you would in an ordinary equation.

Subtract 52 from both sides of the sign. 180 - 52 = 128.

So, 2x is less than or equal to 128.

Divide 128 into two to get 64.

The height of the frame must be 64 inches.

First since the perimeter of this problem is P=2b x 2h I first multiplied 26 by 2 and got 52 inches. then I subtracted 52 from 180 and got 128. From there I divide 128 by 2 and I got 64 for the length

The height must be less than 64in.

Step-by-step explanation:

The formula for the perimeter of a rectangle is:

P=2*W+2*H

Where

P : Perimeter

W: Width

H: Length

So the for a perimeter less the 180in.

180>2*26+2*H

180>52+2H

180-52>2H

128>2H

H<64

So the height must be less than 64in.

Most of the information's required for solving this question is already given. Let us first write them down and then go for finding the answer.

PerimeterĀ of a rectangular picture frame < 180 inches

Width of the rectangular frame = 26 inches

Let us assume the height of the frame = h

Then

2(width + height) < 180

2(26 + h) < 180

52 + 2h < 180

2h < 180 - 52

2h < 128

h < 64

I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

If the perimeter of a rectangular picture frame must be less than 180 in., and the width is 26 in., what must the height h of the frame be?