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In​ 2005, there were 18,100 students at college​ A, with a projected enrollment increase of 1,000

Posted on October 23, 2021 By Swaggaming941 3 Comments on In​ 2005, there were 18,100 students at college​ A, with a projected enrollment increase of 1,000

In​ 2005, there were 18,100 students at college​ A, with a projected enrollment increase of 1,000 students per year. In the same​ year, there were 44,350 students at college​ B, with a projected enrollment decline of 750 students per year. According to these​ projections, when will the colleges have the same​ enrollment? What will be the enrollment in each college at that​ time?

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Comments (3) on “In​ 2005, there were 18,100 students at college​ A, with a projected enrollment increase of 1,000”

  1. Expert says:
    October 23, 2021 at 10:14 am

    26 is 33.33% of 78

    step-by-step explanation:

    26 is what percent of 78?

    26 is p% of 78

    equation: y = p% * x

    solving our equation for p

    p% = y/x

    p% = 26/78

    p = 0.3333

    convert decimal to percent:

    p% = 0.3333 * 100 = 33.33%

    Reply
  2. Expert says:
    October 24, 2021 at 12:34 am

    18

    step-by-step explanation:

    draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

    Reply
  3. kobrien9146 says:
    October 24, 2021 at 1:48 am

    9

    Step-by-step explanation:

    Reply

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