In slope intercept form what is m=8,through(2,-7)

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In slope intercept form what is m=8,through(2,-7)

Y=8x-23

y eqauls eight x minus twenty three

m=8 is the slope

(2,-7) is a point on the line

y = mx + b is the equation

Steps:

(1) fill in what you know

y=8x + b

(2) plug in the coordinate

-7=8(2)+b

(3) solve for b

-7 = 16 + b

-16 -16

-23 = b

(4) plug in what you found out

y = 8x - 23

That would be your answer.

Hope I helped!!

~A

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

[tex]\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)[/tex]

[tex]\text{area of walls and ceiling}=1200+90+120[/tex]

[tex]\text{area of walls and ceiling}=1410[/tex]

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

[tex]\text{ the total painting cost}=10*(\frac{1410}{25})[/tex]

[tex]\text{ the total painting cost}=10*56.4=564[/tex]

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

[tex]\text{area of floor} = 40*3\text{ square meters}[/tex]

[tex]\text{area of floor} =120\text{ square meters}[/tex]

given: 1m squared floor tiles costs $3. so,

[tex]\text{total cost for tiles} = 3*120 = 360[/tex]

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

[tex]\text{combined total cost}= 564+360 = 924[/tex]

therefore, the combined total cost of tiles and paint is $924.

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