In the diagram of circle A, what is m? 75° 90° 120° 135°

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In the diagram of circle A, what is m? 75° 90° 120° 135°

[tex]\angle m=90^o[/tex]

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The measurement of the external angle is the half-difference of the arches that comprise

so

[tex]\angle m=\frac{1}{2}(major\ arc\ LN-minor\ arc\ LN)[/tex]

Remember that the sum of the major arc and a minor arc is equal to 360 degrees

we have

[tex]major\ arc\ LN=270^o[/tex] ----> is given

so

[tex]minor\ arc\ LN=360^o-270^o=90^o[/tex]

substitute the values

[tex]\angle m=\frac{1}{2}(270^o-90^o)=90^o[/tex]

[tex]Circle A is shown. Tangents L M and N M intersect at point M outside of the circle. Arc L N is 270 d[/tex]

90

Step-by-step explanation:

Alright first step what is the degree measure of LN.

A full rotation is 360 degrees so LN=360-270=90.

So angle M is half the difference of the intercepted arcs:

[tex]\frac{1}{2}(270-90)=\frac{1}{2}(180)=90[/tex]

B

Step-by-step explanation:

90

It is in the center