In the parallelogram below find the value of each variable. Hint: find the value of t first

[tex]In the parallelogram below find the value of each variable. Hint: find the value of t first[/tex]

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In the parallelogram below find the value of each variable. Hint: find the value of t first

[tex]In the parallelogram below find the value of each variable. Hint: find the value of t first[/tex]

Don't hold me accountable but I believe if you do 62 divided by 2 and 43 divided by 2 you'd have A and C then subtract those and you'd have B.

62/2=31

43/2=21.5

31 - 21.5 = 9.5

(-4,-5)

Step-by-step explanation:

Here ABCD is a parallelogram,

Where A≡(-2,-1), B≡(2,1), C≡(0,-3) and D≡(x,y)

By the property of parallelogram,

AB║CD, AD║BC, AB = CD and AD=BC

If AB ║ CD

⇒ Slope of AB = Slope of CD

⇒ [tex]\frac{1-(-1)}{2-(-2)} = \frac{-3-y}{0-x}[/tex]

⇒ [tex]\frac{1+1}{2+2)} = \frac{-3-y}{-x}[/tex]

⇒ [tex]\frac{2}{4} = \frac{3+y}{x}[/tex]

⇒ [tex]x=6+2y[/tex]------ (1)

Now, AB = CD

[tex]\sqrt{(2-(-2))^2+(1-(-1))^2} = \sqrt{(0-x)^2+(-3-y)^2}[/tex]

[tex]\sqrt{4^2+2^2} = \sqrt{x^2+9+6y+y^2}[/tex]

[tex]\sqrt{16+4} = \sqrt{x^2+9+6y+y^2}[/tex]

[tex]\sqrt{20} = \sqrt{x^2+9+6y+y^2}[/tex]

[tex]20 = x^2+9+6y+y^2[/tex]

[tex]x^2+6y+y^2=11[/tex]

From equation (1)

[tex](6+2y)^2+6y+y^2=11[/tex]

[tex]36+4y^2+24y+6y+y^2=11[/tex]

[tex]5y^2+30y+25=0[/tex]

[tex]y^2+6y+5=0[/tex]

⇒ y = -1 or -5

Again by equation (1)

for y = -1, x = 4

For y = -5, x = -4

Thus the coordinate of D are (4,-1) or ( -4,-5)

But for D≡(4,-1), AD∦BC

While For D≡(-4,-5) AD ║ BC

Thus the coordinates of D are ( -4,-5)

[tex]If you are given the 3 vertices of a parallelogram below, find the exact coordinates of the 4th vert[/tex]

Angle E=130degrees because those two are congruent. Therefore if you 180-130 you'll get the other angle in the triangle with 70degrees and y. 180-130=50degrees. Then add 50 and 70. 50+70=120degrees. A triangle is supposed to have 180 degrees inside.

180-120=60degrees.

Therefore y=60degrees

TS=17 ,TV=14.

Step-by-step explanation:

Opposite sides of a parallelogram are parallel and equal.

TS=VW

Substituting the values given:

a+15=3a+11

Subtracting a both sides:

15=2a+11

Subtracting 11 both sides:

4=2a or a=2,TS=a+15=2+15=17.

TV=SW( opposite sides of parallelogram are equal)

3b+5=b+11 or 2b=6. or b=3.

TV= 3b+5=3(3)+5=9+5

TV= 14.

TV=14,TS=17.

because this is a parallelogram

=> 3t - 15 = 2t + 10

⇔ t = 10 + 15

⇔ t = 25

with t = 25 => 3t - 15 = 3.25 - 15 = 60

we also have:

4r + (3t - 15) = 180°

⇔ 4r + 60° = 180°

⇒ 4r = 120°

⇔ r = 30

we also have;

4r = 3s

=> 4.30 = 3s

⇔ s = 4.10

⇔ s = 40

Step-by-step explanation:

Step-by-step explanation:

it’s a 30

Who even knows now days

This is useless you will never use this