# Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept

Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b? –15 –9 3 9

## This Post Has 10 Comments

1. nayeli09 says:

-9

Step-by-step explanation:

b = -9.

Step-by-step explanation:

The line passes through (4, 3) and (7, 12). First, we need to find the slope: the rise over the run.

(12 - 3) / (7 - 4) = 9 / 3 = 3.

Now that we have the slope, we can say that m = 3. So, we have an equation of y = 3x + b. To find b, we can use M(4, 3) and say that y = 3 and x = 4.

3 = 3 * 4 + b

b + 12 = 3

b = -9.

Hope this helps!

3. indiareed0orv5ul says:

-9 is the corect answer on edgunity

4. Maaarii says:

b=1

Step-by-step explanation

Vertical difference “y”

Y2-Y1= 7-3=4

Horizontal difference

x2-x1=12-4=8

Slope is =(y2-y1)/(x2-x1)

M=4/8= 1/2

3=1/2(4)+b

3=2+b

b=3-2

B=1

b = -9

Step-by-step explanation:

As we go from M(4, 3) to N(7, 12), x increases by 3 and y increases by 9.  Thus, the slope of the line segment connecting these two points is m = rise / run = m = 9/3, or just m = 3.

Subbing the coordinates of M into y = mx + b, we get:

3 = 3(4) + b, or 3 = 12 + b, so that b = -9.

6. malikxyo224 says:

-9

Step-by-step explanation:

What b represents here is the y intercept.

The first thing we will do here is to find the slope.

Mathematically;

m = (y2-y1)/(x2-x1)

Plugging the values;

m = (12-3)/(7-4) = 9/3 = 3

The equation can thus be written as;

y = 3x + b

To get b, we can use any of the points since they lie on the line

Let’s use point M

Substitute the values of x and y in the equation

3 = 3(4) + b

3 = 12 + b

b = 3-12 = -9

7. serenityarts123 says:

The answer is -9. hope it helps

8. randkphillipsp5v56r says:

its B on E2020

Step-by-step explanation:

9. ineedhelpasap12 says:

-9

This should be right. Hope this helped

10. Thejollyhellhound20 says:

For finding the value of b, we must consider that Line MN passes through points M(4, 3) and N(7, 12). With this condition y = mx + b, can be written 3=4m+ b (because line passes through M(4,3) ) and 12=7m+b, b ( because line passes through M(7,12)). We have a system of equation 4m+ b=3 7m+b=12 For solving this, 4m+b- (7m+b)= 3-12, it is equivalent to -3m= -9 and then m=3, if m=3 so 4x3 +b =3 implies b= 3 -12= -9, so the value of b= -9