Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?
Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?
Time, t = 3.125 s
Step-by-step explanation:
The height attained by the ball after it was kicked is given by as a function of time t as :
[tex]h=-16t^2+50t[/tex]
It is required to find the time until which the ball hits the ground. At that point, h(t) = 0
So,
[tex]-16t^2+50t=0\\\\t(-16t+50)=0\\\\t=0, -16t+50=0\\\\t=0, 3.125\ s[/tex]
So, 3.125 seconds before the ball hit the ground.
25/8 or 3.125 seconds
Step-by-step explanation:
To determine the time until the ball hits the ground, you need to solve the quadratic as the height equals zero.
0 = -16t^2+50t
This gives us a classing quadratic that you can factor or use the quadratic formula to solve.
x = 0, x = 25/8
If you graph this, think of y = 0 as the ground, so when the parabola intersects the x-axis on the right that represents how much time would have passed.