On chatty cathy’s cell phone plan she pays for minutes used plus a fixed monthly charge.

On chatty cathy’s cell phone plan she pays for minutes used plus a fixed monthly charge. for 500 minutes she pays $35 total, and for 1500 minutes used she pays $55 total. what is her monthly fixed charge?

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  1.   the correct choice is marked

    step-by-step explanation:

    the first two graphs show multiple turning points. the last graphs matches the description in every detail.

  2. C) $25

    Step-by-step explanation:

    $25 is correct. The slope of the line from (35, 500) to 55, 1500) is 20/1000 = .02, which is her cost per minute. Plug in one of the points into the equation y = mx + b to find b, which is the fixed cost.

    Hope this helps

    -Amelia

  3. Answer

    Find out  the what is her monthly fixed charge .

    To prove

    Let us assume that the cost per mintues = x

    Let us assume that the monthly charge be = y

    As given

    n Chatty Cathy’s cell phone plan she pays for minutes used plus a fixed monthly charge.

    For 500 minutes she pays $35 total

    Than the equation becomes

    500x + y = 35

    As given

    for 1500 minutes used she pays $55 total.

    Than the equation becomes

    1500x + y = 55

    Subtracted 500x + y = 35 from 1500x + y = 55

    1500x - 500x + y - y = 55 - 35

    1000x = 20

    [tex]x = \frac{20}{1000}[/tex]

    x = $0.02

    Put in the  500x + y = 35

    500 × 0.02 + y = 35

    10 + y = 35

    y = 35 - 10

    y = $25

    Therefore the monthly fixed charge be $25.

  4. problem:

    f(x) = - 2/3x + 5; f(5/2)

    substitute 5/2 in for x:

    f(5/2) = -2/3(5/2) + 5

    simplify the right side:

    f(5/2) = -5/3 + 5

    f(5/2) = 10/3

    f(5/2) = 10/3

    i hope this !

  5. We are given : For 500 minutes she pays $35 total and for 1500 minutes used she pays $55 total.

    So, we can put the given information in form of two coordinates :

    ( Number of minutes, Total amount).

    (500, 35) and (1500, 55).

    First we need to find the slope between those two coordinates.

    [tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

    [tex]\left(x_1,\:y_1\right)=\left(500,\:35\right),\:\left(x_2,\:y_2\right)=\left(1500,\:55\right)[/tex]

    [tex]m=\frac{55-35}{1500-500}[/tex]

    [tex]m=\frac{1}{50}[/tex]

    Now applying slope-intercept form y=mx+b, where m is the slope and b is y-intercept.

    y-intercept represents monthly fixed charge.

    Plugging (x,y) = (500, 35) and slope m= 1/50 in slope-intercept form y=mx+b.

    35 = 1/50 (500) +b

    35 = 10 + b.

    Subtracting 10 from both sides, we get

    35-10 = 10-10 + b

    b = 25.

    Therefore, her monthly fixed charge is $25.

  6. $25

    Step-by-step explanation:

    500 mins = $35 (fixed + per minute charge)

    1500 mins = $55 (fixed + per minute charge)

    If we let per minute charge be "m"

    and

    let fixed charge be "f"

    we can write 2 equations as:

    35 = 500m + f

    and

    55 = 1500m + f

    Now,

    We re-write both equations in terms of f and equate both expressions:

    f = 35 - 500m

    and

    f = 55 - 1500m

    Equating:

    35 - 500m = 55 - 1500m

    -500m + 1500m = 55 - 35

    1000m = 20

    m = 20/1000

    m = 0.02

    Now we find f, what we are looking for:

    f = 35 - 500m

    f = 35 - 500(0.02)

    f = 25

    So, the fixed charge is $25

  7. Option 'C' is correct.

    Step-by-step explanation:

    Let the fixed monthly charges be x

    Let the charges per minutes be y

    According to question, we have

    [tex]x+500y=\$35\\x+1500y=\$55[/tex]

    Now, by using the method of substitution  for solving the system of linear equation:

    [tex]x=35-500y\\\\\text{ put in second equation i.e.}x+1500y=\$55\\\\35-500y+1500y=55\\\\35+1000y=55\\\\1000y=55-35\\\\1000y=20\\\\x=\frac{20}{1000}\\\\x=\frac{1}{50}[/tex]

    Now, put the value of y in x , so we get,

    [tex]x=35-500y\\\\x=35-500\times\frac{1}{50}\\\\x=35-10=\$25[/tex]

    Hence, the monthly fixed charge is $25

    Thus, Option 'C' is correct.

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