On the graph below are three points x, y, ans z. write the coordinates for the given dilation. do, 3 of x = a. (7, 3) b. (12, 0) c. (1, -3) the graph points are y as (3,2) x as (4,0) and z as (2,-2)
On the graph below are three points x, y, ans z. write the coordinates for the given dilation. do, 3 of x = a. (7, 3) b. (12, 0) c. (1, -3) the graph points are y as (3,2) x as (4,0) and z as (2,-2)
The center of the dilation is the origin, and the scale factor is 2.
To find the coordinates of the points under this transformation, it is enough to multiply both coordinates of the points X, Y, and Z by 2.
Take a look at the dilation of point Z. To get to Z', both the x and y coordinate of Z must be multiplied by 2.
So, the coordinates are:
X'(8, 0); Y'(6, 4); Z'(4, -4).
[tex]on the graph below are three points x, y, and z. write the coordinates for the given dilation. do, 2[/tex]
[tex](-\frac{3}{2},-1)[/tex]
Step-by-step explanation:
From the graph in the attachment Y has coordinates:Y(3,2)
The transformation rule for a dilation with a scale factor k about the origin is:
[tex](x,y)\to (kx,ky)[/tex]
In this case we have [tex]k=-\frac{1}{2}[/tex]
We substitute the coordinates and [tex]k=-\frac{1}{2}[/tex] to get:
[tex]Y(3,2)\to Y'(-\frac{1}{2}*3,-\frac{1}{2}*2)[/tex]
This simplifies to:
[tex]Y(3,2)\to Y'(-\frac{3}{2},-1)[/tex]
The first choice is correct.
[tex]On the graph below are three points x, y, and z. write the coordinates for the given dilation. do, -[/tex]
[tex]On the graph below are three points x, y, and z. write the coordinates for the given dilation. do, -[/tex]
(-3/2, -1)
(3/2, 1)
(5/2, 3/2)
Step-by-step explanation:
The first thing you should see in this case are the coordinates of point X which are given by:
x = (4,0)
Applying the given dilatation:
DO, 3
X = (3 * 4.3 * 0)
X = (12.0)
answer
the coordinates for the given dilation. DO, 3 of X are
B. (12, 0)
B 12 and 0
Step-by-step explanation:
2, - 2 is the answer
Step-by-step explanation:
Step-by-step explanation: EXPLANATION From the graph, the coordinates of Y are: We want to find the image of this point after a dilation by a scale factor of -½ about the origin. The rule for the dilation is : To find the coordinates of Y', we plug the coordinates of Y. The first choice is correct. Fraction: - 3/2, -1
ANSWER
[tex]( - \frac{3}{2} , - 1)[/tex]
EXPLANATION
From the graph, the coordinates of Y are:
[tex](3,2)[/tex]
We want to find the image of this point after a dilation by a scale factor of -½ about the origin.
The rule for the dilation is :
[tex](x,y)\to( - \frac{1}{2} x, - \frac{1}{2} y)[/tex]
To find the coordinates of Y', we plug the coordinates of Y.
[tex]Y(3,2)\to \: Y'( - \frac{1}{2} (3), - \frac{1}{2}(2) )[/tex]
[tex]Y(3,2)\to \: Y'( - \frac{3}{2}, - 1)[/tex]
The first choice is correct.