Parker is planning to build a playhouse for his sister. The scaled model below gives the reduced measures for width and height. The width of the playhouse is 22 centimeters and the height is 10 centimeters. Not drawn to scale The yard space is large enough to have a playhouse that has a width of 3.5 meters. If Parker wants to keep the playhouse in proportion to the model, what cross multiplication of the proportion should he use to find the height? (3.5) (10) = 3.5 x (3.5) (22) = 3.5 x (10) (3.5) = 22 x (1) (22) = 3.5 x

The cross multiplication of the proportion he should use to find the height of the playhouse is [tex]H=\frac{3.5y}{x}[/tex]

Step-by-step explanation:

Since we have given that

Width of the playhouse = 3.5 m

Let the height of the playhouse be 'H'.

If Parker wants to keep the playhouse in proportion to the model.

Let the width of the model be 'x.

Let the height of the model be 'y'.

So, the proportion becomes,

[tex]\frac{W}{H}=\frac{x}{y}\\\\\frac{3.5}{H}=\frac{x}{y}\\\\H=\frac{3.5y}{x}[/tex]

Hence, the cross multiplication of the proportion he should use to find the height of the playhouse is [tex]H=\frac{3.5y}{x}[/tex]

C

I took the test

15.5

Step-by-step explanation:

define

W= width playhouse real=3.5

H= height playhouse real

x=width playhouse model

y=height playhouse model

therefore

H/W=y/x>H=y*W/x>H=3.5*y/x

The answer is 3.5*y/x to find the height H

The cross multiplication would be 10(350) = 22(x).

Step-by-step explanation:

We would first convert meters to centimeters. There are 100 cm in a meter; this means 3.5 m = 3.5(100) = 350 cm.

The ratio of the height to base of the model is 10/22. The ratio of the playhouse would then be x/350. This gives us

10/22 = x/350

Cross multiplying, we would have 10(350) = 22(x).

así que si usted toma el número sesenta dos entonces se obtiene cuarenta y seis

Step-by-step explanation:

C)

its c (10)(3.5)=22x

Step-by-step explanation:

ed 2020