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## This Post Has 9 Comments

1. robert7248 says:

Line 2 = Rewrite with a common baseLine 3 = Power of a Power PropertyLine 4 = Property of EqualityMax made an error in line  3  The correct solution is x =  7

Explanation:

Since 25 is equal to 5^2, we use this fact to help get everything as a common base. That common base is 5. That way, we take advantage of the fact that if a^b = a^c, then b = c. In other words, if the two sides are the same, with the same base, then the exponents must be equal as well. This is the property of equality (one form of it).

The power of a power property is used in line 3. This rule is (a^b)^c = a^(b*c). When writing some exponential to another power, we multiply the exponents while keeping the base the same.

Max made a mistake in line 3 when he multiplied the exponents on the left side. The exponents 2 and (x-2) multiply to 2x-4 and not 2x-2. He forgot to distribute fully.

The equation he needs to solve is 2x-4 = x+3

The steps to solving would be something along the lines of this

2x-4 = x+3

2x-x = 3+4

x = 7

Though there are other paths you could take.

As a way to check the answer, we plug x = 7 into the original equation and simplify both sides

25^(x-2) = 5^(x+3)

25^(7-2) = 5^(7+3)

25^5 = 5^10

9,765,625 = 9,765,625

We get the same thing on both sides, so this confirms the answer.

Let's check x = 5 to see how/why it doesn't work

25^(x-2) = 5^(x+3)

25^(5-2) = 5^(5+3)

25^3 = 5^8

15,625 = 390,625

We get two different results on either side. This is a contradiction since the left side says one thing, but the right side says another. This shows that x = 5 is not a solution.

2. lulustar13 says:

Given:

The frequency distribution table.

To find:

The mean average score on a test.

Solution:

The frequency distribution table is

$Marks (x_i)$                   $Frequency(f_i)$                  $f_ix_i$

x                                     a                               xa

y                                     b                               yb

z                                     c                               zc

Sum                              a+b+c                          xa+yb+zc

Now, the mean average score on the test is

$Mean=\dfrac{\sum f_ix_i}{\sum f_i}$

$Mean=\dfrac{xa+yb+zc}{a+b+c}$

Therefore, the mean average score on the test is $\dfrac{xa+yb+zc}{a+b+c}$.

3. ugtguytu8528 says:

Explanation:

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4. lovabletenthasan says:

3x

Step-by-step explanation:

givens: x=4

3(4)+3=15

12+3=15

15=15

The first option is correct, therefore the answer is 3x

5. Expert says:

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step-by-step explanation:

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6. Expert says:

step-by-step explanation: p-4p

7. axelsanchez7710 says:

Hello!

$\large\boxed{x = 17}$

$\sqrt{x -1} + 5 = 9$

Begin by subtracting 5 from both sides:

$\sqrt{x -1} = 9 - 5\\\\\sqrt{x -1} = 4$

Square both sides to get rid of the radical:

$x - 1 = 16$

Add 1 to both sides to completely isolate for x:

$x = 17$

8. joshbee2014 says:

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9. destinymitchell966 says:

The mean is the total of the numbers divided by how many numbers there are. To find the mean, add all the numbers together then divide by the number of numbers. Eg 6 + 3 + 100 + 3 + 13 = 125 ÷ 5 = 25 The mean is 25.

Step-by-step explanation: