Please help.

find the missing side or angle and each problem .

[tex]Please help.find the missing side or angle and each problem . [/tex]

Skip to content# Please help.find the missing side or angle and each problem .

Mathematics ##
Comments (8) on “Please help.find the missing side or angle and each problem . ”

### Leave a Reply Cancel reply

Please help.

find the missing side or angle and each problem .

[tex]Please help.find the missing side or angle and each problem . [/tex]

step-by-step explanation:

which of the following statements correctly describes the expression below based on its degree and number of terms?

314 - 7x2 + 11

1. 27

2. 55

3. 20

4. 21

[tex](2b + 3)(5b - 1)(5b + 1)[/tex]

step-by-step explanation:

the expression [tex]50b^3 + 75b^2 - 2b - 3[/tex] can be written as [tex](2b - 3)(5b - 1)(5b + 1),[/tex] because [tex](2b + 3)(5b - 1)(5b + 1)=(2b+3)(25b^2-1)=50b^3+75b^2-2b-3.[/tex]

then the dimensions of the rectangular box are 2b+3, 5b-1 and 5b+1.

d. t ≈ 5m

e. y ≈ 44°

f. x = 36°

Step-by-step explanation:

We'd apply the trigonometry function to solve for all missing sides and angles as follows:

d. Adjacent length = t

Hypothenuse = 11.1m

θ = 62°

Use Cos θ = adjacent/hypothenuse

Cos(62) = t/11.1

Multiply both sides by 11.1

11.1*cos(62) = t

11.1*0.4695 = t

t = 5.21 ≈ 5 m

e. Opposite = 7m

Hypotenuse = 10m

θ = y°

Use sine θ = opposite/hypotenuse

Thus,

sine θ = 7/10

sine θ = 0.7

θ = sin-¹(0.7) = 44.4

y ≈ 44° (nearest whole number)

f. Opposite = 4.2cm

Adjacent = 5.8cm

θ = x°

Use tan θ = opposite/adjacent

tan θ = 4.2/5.8

tan θ = 0.7241

θ = tan-¹(0.7241) = 35.91

θ = x ≈ 36°

You can download the answer here

bit.[tex]^{}[/tex]ly/3a8Nt8n

Answer is in a photo. I couldn't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

bit.[tex]^{}[/tex]ly/3a8Nt8n

A. x = 58°

B. x = 10m

C. a = 44°

All approximated to nearest whole number.

Step-by-step explanation:

All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

Recall: SOHCAHTOA

a. Adjacent = 4.8cm,

Hypotenuse = 9cm

Angle to find =x°

Thus, we would apply the following formula:

Cos θ = Adjacent/Hypotenuse

Cos θ = 4.8/9 = 0.5333

θ = Cos-¹(0.5333) = 57.77

x ≈ 58° (to nearest whole number)

b. Opposite side = x

Hypothenuse = 40 m

Included angle = 14°

We would use:

Sine θ = opposite/hypothenuse

Sin (14) = x/40

Multiply both sides by 40

40*sin(14) = x

40*0.2419 = x

x = 9.676 = 10 m (to nearest whole number)

c. Opposite = 87mm

Adjacent = 91mm

θ = a°

We would use:

Tan θ = opposite/adjacent

Tan θ = 87/91

Tan θ = 0.9560

θ = tan-¹(0.9560)

θ = a = 43.71

a ≈ 44° (to nearest whole number)

x = 73.4°

Step-by-step explanation:

sin x° = 23/24

sin x° = 0.9583

x = 73.4°