Please help.find the missing side or angle and each problem . ​

Please help.
find the missing side or angle and each problem .


[tex]Please help.find the missing side or angle and each problem . ​[/tex]

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  1. step-by-step explanation:

    which of the following statements correctly describes the expression below based on its degree and number of terms?

    314 - 7x2 + 11

  2. [tex](2b + 3)(5b - 1)(5b + 1)[/tex]

    step-by-step explanation:

    the expression [tex]50b^3 + 75b^2 - 2b - 3[/tex] can be written as [tex](2b - 3)(5b - 1)(5b + 1),[/tex] because [tex](2b + 3)(5b - 1)(5b + 1)=(2b+3)(25b^2-1)=50b^3+75b^2-2b-3.[/tex]

    then the dimensions of the rectangular box are 2b+3, 5b-1 and 5b+1.

  3. d. t ≈ 5m

    e. y ≈ 44°

    f. x = 36°

    Step-by-step explanation:

    We'd apply the trigonometry function to solve for all missing sides and angles as follows:

    d. Adjacent length = t

    Hypothenuse = 11.1m

    θ = 62°

    Use Cos θ = adjacent/hypothenuse

    Cos(62) = t/11.1

    Multiply both sides by 11.1

    11.1*cos(62) = t

    11.1*0.4695 = t

    t = 5.21 ≈ 5 m

    e. Opposite = 7m

    Hypotenuse = 10m

    θ = y°

    Use sine θ = opposite/hypotenuse

    Thus,

    sine θ = 7/10

    sine θ = 0.7

    θ = sin-¹(0.7) = 44.4

    y ≈ 44° (nearest whole number)

    f. Opposite = 4.2cm

    Adjacent = 5.8cm

    θ = x°

    Use tan θ = opposite/adjacent

    tan θ = 4.2/5.8

    tan θ = 0.7241

    θ = tan-¹(0.7241) = 35.91

    θ = x ≈ 36°

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  6. A. x = 58°

    B. x = 10m

    C. a = 44°

    All approximated to nearest whole number.

    Step-by-step explanation:

    All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

    Recall: SOHCAHTOA

    a. Adjacent = 4.8cm,

    Hypotenuse = 9cm

    Angle to find =x°

    Thus, we would apply the following formula:

    Cos θ = Adjacent/Hypotenuse

    Cos θ = 4.8/9 = 0.5333

    θ = Cos-¹(0.5333) = 57.77

    x ≈ 58° (to nearest whole number)

    b. Opposite side = x

    Hypothenuse = 40 m

    Included angle = 14°

    We would use:

    Sine θ = opposite/hypothenuse

    Sin (14) = x/40

    Multiply both sides by 40

    40*sin(14) = x

    40*0.2419 = x

    x = 9.676 = 10 m (to nearest whole number)

    c. Opposite = 87mm

    Adjacent = 91mm

    θ = a°

    We would use:

    Tan θ = opposite/adjacent

    Tan θ = 87/91

    Tan θ = 0.9560

    θ = tan-¹(0.9560)

    θ = a = 43.71

    a ≈ 44° (to nearest whole number)

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