PLEASE HELP IM BEING TIMED Part A: What is the approximate yintercept of the line of best fit and what does it represent?
Part B: Write the equation for the line of best it in the slopeintercept form and use it to predict the number of matches that could be won after 13 months of practice. Show your work and include the points used to calculate the slope.
[tex]PLEASE HELP IM BEING TIMED Part A: What is the approximate yintercept of the line of best fit an[/tex]
Part A: The approximate yintercept is 3. The yintercept is like the starting point of the information. in this case the yintercept represents the number of matches won with no months of practice.
Part B: The slope is 7/4. Using the equation y = 7/4 x 13 + 3, The answer is approximately 26 (25.75). So after 13 months of practice they won approximately 26 times.
Hope This Helps!
First we have to understand that a Yintercept of a line is the point where a line’s graph intersects or crosses the Yaxis. In this case we will need to look at the graph in order to find the Yintercept. Looking at the graph I would say that the Yintercept is (0,3.5).
For part B you can use the following:
y = m x + b
y = (7/4) * 13 + 3
26
I hope it helps, Regards.
[tex]The graph shows the relationship between the number of months different students practiced tennis an[/tex]
Part A  The approximate yintercept of the line is 3. It represents the “starting point”. So when you practiced for 0 months (no practice at all) you won 2 matches
Stepbystep explanation:
The line has y intercept as the value of y, when x=0
y intercept =3.5
Part B:
The graph passes through two points as (0,3.5) and (5,12)
Hence slope= change in y coordinate/change in x coordinate
=[tex]\frac{(123.5)}{(50)} =1.7[/tex]
Hence regression line is
y =1.7x+3.5
When x=13
y = 1.7(13)+3.5
= 25.6
For the answer to the question above,
First, we have to understand that a Yintercept of a line is the point where a line’s graph intersects or crosses the Yaxis. In this case, we will need to look at the graph in order to find the Yintercept. Looking at the graph I would say that the Yintercept is (0,3.5).
For part B you can use the following:
y = m x + b
y = (7/4) * 13 + 3
26
I hope my answer helped you.
Part A : yintercept is approximately 3.25
Part B : equation of the line is
[tex]y=\frac{7}{4}x+\frac{13}{4}[/tex]
Slope is [tex]\frac{7}{4}[/tex]
The number of matches would be 26 after 13 months of practice.
Stepbystep explanation:
By the given diagram,
The line is passes through the points (1, 5) and (5,12),
∵ equation of a line passes through the point [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
[tex]yy_1=\frac{x_2x_1}{y_2y_1}(xx_1)[/tex]
Thus, the equation of the line would be,
[tex]y5=\frac{125}{51}(x1)[/tex]
[tex]y5=\frac{7}{4}(x1)[/tex]
[tex]y5=\frac{7x}{4}\frac{7}{4}[/tex]
[tex]y=\frac{7}{4}x\frac{7}{4}+5\implies y=\frac{7x}{4}+\frac{13}{4}[/tex]
Part A : Now, if x = 0,
[tex]\implies y=\frac{13}{4}\approx 3.25[/tex]
Hence, the yintercept of the line would be approx 3.25,
Part B:
The slope intercept form of a line is,
y = mx + c
Where, m is the slope,
Hence, the slope intercept form of the line is,
[tex]y=\frac{7}{4}x+\frac{13}{4}[/tex]
Having slope [tex]\frac{7}{4}[/tex]
If x = 13,
[tex]y=\frac{7}{4}(13)+\frac{13}{4}= \frac{91}{4}+\frac{13}{4}=\frac{104}{4}=26[/tex]
Therefore, the number of matches would be 26 after 13 months of practice.
Part a: what is the approximate yintercept of the line of best fit and what does it represent? the approximate yintercept of the line of best fit is (0, 3.3) and it represents the number of matches a player would win if the player doesn't practice any month.part b: write the equation for the line of best fit in the slopeintercept form and use it to predict the number of matches that could be won after 13 months of practice show your work and include the points used to calculate the slope.y=mx+bm=(y2y1)/(x2x1)taking: p1=(0,3.3)=(x1,y1)→x1=0, y1=3.3p2=(6,13.5)=(x2,y2)→x2=6, y2=13.5m=(13.53.3)/(60)m=10.2/6m=1.7b=3.3y=mx+by=1.7x+3.3the equation for the line of best fit in the slopeintercept form is y=1.7x+3.3number of matches that could be won after 13 months of practicex=13→y=1.7(13)+3.3y=22.1+3.3y=25.4the number of matches that could be won after 13 months of practice is approximately 25
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Stepbystep explanation:
The y intercept is 3 and plz mark me
This is Hard but I tried Hope this Helps.
222+20 = 0x=12.2 y


x_

20.5 
2 10 
1 
m=Months 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
1 is 3 and 2 is y 2/1x
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stepbystep explanation:
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