PLEASE HELP IM BEING TIMEDPart A: What is the approximate y-intercept of the line of best fit and what does it represent?Part B: Write

PLEASE HELP IM BEING TIMED Part A: What is the approximate y-intercept of the line of best fit and what does it represent?
Part B: Write the equation for the line of best it in the slope-intercept form and use it to predict the number of matches that could be won after 13 months of practice. Show your work and include the points used to calculate the slope.


[tex]PLEASE HELP IM BEING TIMED Part A: What is the approximate y-intercept of the line of best fit an[/tex]

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  1. Part A: The approximate y-intercept is 3. The y-intercept is like the starting point of the information. in this case the y-intercept represents the number of matches won with no months of practice.

    Part B: The slope is 7/4. Using the equation y = 7/4 x 13 + 3, The answer is approximately 26 (25.75). So after 13 months of practice they won approximately 26 times.

    Hope This Helps!

  2. First we have to understand that a Y-intercept of a line is the point where a line’s graph intersects or crosses the Y-axis. In this case we will need to look at the graph in order to find the Y-intercept. Looking at the graph I would say that the Y-intercept is (0,3.5).

    For part B you can use the following:

    y = m x + b 
    y = (7/4) * 13 + 3 
    26

    I hope it helps, Regards.

    [tex]The graph shows the relationship between the number of months different students practiced tennis an[/tex]

  3. Part A - The approximate y-intercept of the line is 3. It represents the “starting point”. So when you practiced for 0 months (no practice at all) you won 2 matches

  4. Step-by-step explanation:

    The line has y intercept as the value of y, when x=0

    y intercept =3.5

    Part B:

    The graph passes through two points as (0,3.5) and (5,12)

    Hence slope= change in y coordinate/change in x coordinate

    =[tex]\frac{(12-3.5)}{(5-0)} =1.7[/tex]

    Hence regression line is

    y =1.7x+3.5

    When x=13

    y = 1.7(13)+3.5

    = 25.6

  5. For the answer to the question above, 

    First, we have to understand that a Y-intercept of a line is the point where a line’s graph intersects or crosses the Y-axis. In this case, we will need to look at the graph in order to find the Y-intercept. Looking at the graph I would say that the Y-intercept is (0,3.5).

    For part B you can use the following:

    y = m x + b 
    y = (7/4) * 13 + 3 
    26

    I hope my answer helped you.

  6. Part A : y-intercept is approximately 3.25

    Part B : equation of the line is

    [tex]y=\frac{7}{4}x+\frac{13}{4}[/tex]

    Slope is [tex]\frac{7}{4}[/tex]

    The number of matches would be 26 after 13 months of practice.

    Step-by-step explanation:

    By the given diagram,

    The line is passes through the points (1, 5) and (5,12),

    ∵ equation of a line passes through the point [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,

    [tex]y-y_1=\frac{x_2-x_1}{y_2-y_1}(x-x_1)[/tex]

    Thus, the equation of the line would be,

    [tex]y-5=\frac{12-5}{5-1}(x-1)[/tex]

    [tex]y-5=\frac{7}{4}(x-1)[/tex]

    [tex]y-5=\frac{7x}{4}-\frac{7}{4}[/tex]

    [tex]y=\frac{7}{4}x-\frac{7}{4}+5\implies y=\frac{7x}{4}+\frac{13}{4}[/tex]

    Part A : Now, if x = 0,

    [tex]\implies y=\frac{13}{4}\approx 3.25[/tex]

    Hence, the y-intercept of the line would be approx 3.25,

    Part B:

    The slope intercept form of a line is,

    y = mx + c

    Where, m is the slope,

    Hence, the slope intercept form of the line is,

    [tex]y=\frac{7}{4}x+\frac{13}{4}[/tex]

    Having slope [tex]\frac{7}{4}[/tex]

    If x = 13,

    [tex]y=\frac{7}{4}(13)+\frac{13}{4}= \frac{91}{4}+\frac{13}{4}=\frac{104}{4}=26[/tex]

    Therefore, the number of matches would be 26 after 13 months of practice.

  7. Part a: what is the approximate y-intercept of the line of best fit and what does it represent? the approximate y-intercept of the line of best fit is (0, 3.3) and it represents the number of matches a player would win if the player doesn't practice any month.part b: write the equation for the line of best fit in the slope-intercept form and use it to predict the number of matches that could be won after 13 months of practice show your work and include the points used to calculate the slope.y=mx+bm=(y2-y1)/(x2-x1)taking: p1=(0,3.3)=(x1,y1)→x1=0, y1=3.3p2=(6,13.5)=(x2,y2)→x2=6, y2=13.5m=(13.5-3.3)/(6-0)m=10.2/6m=1.7b=3.3y=mx+by=1.7x+3.3the equation for the line of best fit in the slope-intercept form is y=1.7x+3.3number of matches that could be won after 13 months of practicex=13→y=1.7(13)+3.3y=22.1+3.3y=25.4the number of matches that could be won after 13 months of practice is approximately 25

  8. This is Hard but I tried Hope this Helps.
    22-2+20 = 0x=12.2        |y
                                          |
                                          | 
                      |x_
                                          |
                          20.5                | 
                   2             10         |
                   1                       |
    m=Months 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

  9. i dont give a fuuuuuuuuuuuuuuuuuuuuuuuuukkkkkkkkkkkkkkkkkkkkk

    step-by-step explanation:

    [tex]How do i make a table and equation out of hexagons[/tex]

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