Please HELP ] Segment AB has point A located at (8, 9). If the distance from A to B is 10 units, which of the following could be used to calculate the coordinates for point B (5 points)

10 = square root of the quantity of x plus 8 all squared plus y plus 9 all squared

10 = square root of the quantity of x plus 9 all squared plus y plus 8 all squared

10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared

10 = square root of the quantity of x minus 9 all squared plus y minus 8 all squared

d

step-by-step explanation:

d

6hope this ! ! ’

the third one

Step-by-step explanation:

We have A(8.9) and B(x,y)

so vector AB(x-8,y-9)

Then :

10= [tex]\sqrt{(x-8)^{2}+(y-9)^{2} }[/tex]

I chose 10 = square root of the quantity of x minus 9 all squared plus y minus 8 all squared on the test and got it right.

Let B = (x, y)

Given A = (8, 9)

[tex]distance = \sqrt{(x_1 - x_2)^2 + (y_1-y_2)^2} \\\\10 = \sqrt{(x_1 - 8)^2 + (y_1-9)^2}[/tex]

option 3

10=square the third one down

I think 10 bedside of the quantity of nine divide in the quantity of 8 minus the squared root plus the sub total