the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.
step-by-step explanation:
[tex]Which are the possible side lengths of a triangle?[/tex]
a
step-by-step explanation:
the answer is a
You put the x in the x area and solve the problem.
For example:
For 0 you would do y=-7(0) + 9
Then if you do the math you get y = 9
Therefore, your answer is 9.
-7x+8y=39
x=-9
-7×-9+8y=39
63+8y=39
8y=39-63
8y=-24
y=-24÷8
y=-3
-7x + 8y = 39
when x = -9
-7(-9) +8y = 39
63 + 8y = 39
8y = 39-63
8y = -24
Divide both sides by 8
y = - 3
Hope this helps.
the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.
step-by-step explanation:
[tex]Which are the possible side lengths of a triangle?[/tex]
y = -3
Step-by-step explanation:
=> -7x+8y = 39
Putting x = -9
=> -7(-9)+8y = 39
=> 63+8y = 39
Subtracting 63 to both sides
=> 8y = 39-63
=> 8y = -24
Dividing both sides by 8
=> y = -3