Points B and D are points of tangency. Find the value of x.
[tex]Points B and D are points of tangency. Find the value of x.[/tex]
Points B and D are points of tangency. Find the value of x.
[tex]Points B and D are points of tangency. Find the value of x.[/tex]
step-by-step explanation:
the options are kind of confusing. i can tell you what i see going on here when i look at the graph.
the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]
alam ko sagot pero mataas lang
In both cases,
[tex]AB^2=AD^2[/tex]
(as a consequence of the interesecting secant-tangent theorem)
So we have
10.
[tex](4x+7)^2=(6x-3)^2[/tex]
[tex]16x^2+56x+49=36x^2-36x+9[/tex]
[tex]20x^2-92x-40=0[/tex]
[tex]5x^2-23x-10=0[/tex]
[tex](5x+2)(x-5)=0\implies\boxed{x=5}[/tex]
(omit the negative solution because that would make at least one of AB or AD have negative length)
11.
[tex](4x^2-18x-10)^2=(x^2+x+4)^2[/tex]
[tex]16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16[/tex]
[tex]15x^4-146x^3+235x^2+352x+84=0[/tex]
[tex](x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}[/tex]
(again, omit the solutions that would give a negative length for either AB or AD)
Step-by-step explanation:
5x-8=2x+7
3x=15
x=5
Step-by-step explanation:
to be honest with you idk but your probaly wondering then y are you answering this if u dont know we its all about the points so if i answer this then i get points and i need need points to help me on my stupid homwork. plz say thanks to this and give me a five star rating, help a sis out, also i rember doing this like a month ago but i complete forgot cause it was not important, good luck on your homwork tho, feel free to do the same thing on my questions!
answer:
3 bags of apples and 2 bags of oranges.
step-by-step explanation: