Points B and D are points of tangency. Find the value of x.

[tex]Points B and D are points of tangency. Find the value of x.[/tex]

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Points B and D are points of tangency. Find the value of x.

[tex]Points B and D are points of tangency. Find the value of x.[/tex]

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

alam ko sagot pero mataas lang

In both cases,

[tex]AB^2=AD^2[/tex]

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

[tex](4x+7)^2=(6x-3)^2[/tex]

[tex]16x^2+56x+49=36x^2-36x+9[/tex]

[tex]20x^2-92x-40=0[/tex]

[tex]5x^2-23x-10=0[/tex]

[tex](5x+2)(x-5)=0\implies\boxed{x=5}[/tex]

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

[tex](4x^2-18x-10)^2=(x^2+x+4)^2[/tex]

[tex]16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16[/tex]

[tex]15x^4-146x^3+235x^2+352x+84=0[/tex]

[tex](x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}[/tex]

(again, omit the solutions that would give a negative length for either AB or AD)

Step-by-step explanation:

5x-8=2x+7

3x=15

x=5

Step-by-step explanation:

to be honest with you idk but your probaly wondering then y are you answering this if u dont know we its all about the points so if i answer this then i get points and i need need points to help me on my stupid homwork. plz say thanks to this and give me a five star rating, help a sis out, also i rember doing this like a month ago but i complete forgot cause it was not important, good luck on your homwork tho, feel free to do the same thing on my questions!

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: