# Points B and D are points of tangency. Find the value of x.

Points B and D are points of tangency. Find the value of x.

$Points B and D are points of tangency. Find the value of x.$

## This Post Has 6 Comments

1. Expert says:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. 

2. jescanarias22 says:

alam ko sagot pero mataas lang

3. jholland03 says:

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

4. santiagoagilg says:

Step-by-step explanation:

5x-8=2x+7

3x=15

x=5

5. reyne36 says:

Step-by-step explanation:

to be honest with you idk but your probaly wondering then y are you answering this if u dont know we its all about the points so if i answer this then i get points and i need need points to help me on my stupid homwork. plz say thanks to this and give me a five star rating, help a sis out, also i rember doing this like a month ago but i complete forgot cause it was not important, good luck on your homwork tho, feel free to do the same thing on my questions!

6. Expert says: