Prepare 320 teddy bears to include in your donation your associate can’t repair eight teddy bears an hour and uses 34 yards of ribbon in doing so she need you to buy the ribbon but the craft store only sales rep is in pete how many feet of ribbon are needed

ωєℓℓ ωιтн тнαт ιиfσ

тнє вαѕє ιѕ 30

αи∂ тнє нєιgнтн ιѕ 30

нσρє ι ¢συℓ∂ нєℓρ

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the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

look at the picture.

[tex]efgh\sim abcd\to2: 3[/tex]

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

[tex]6: 3x=2: 3\to\dfrac{6}{3x}=\dfrac{2}{3}\to\dfrac{2}{x}=\dfrac{2}{3}\to2x=(2)(3)\to x=3[/tex]

use pythagorean theorem:

[tex]a^2=8^2+(2\cdot3)^2\\\\a^2=64+36\\\\a^2=100\to a=\sqrt{100}\to a=10\ cm[/tex]

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

[tex]p_{efgh}: p_{abcd}=2: 3\to\dfrac{p_{efgh}}{p_{abcd}}=\dfrac{2}{3}[/tex]

substitute:

[tex]\dfrac{p_{efgh}}{30}=\dfrac{2}{3}[/tex] cross multiply

[tex]3p_{efgh}=(30)(2)[/tex] divide both sides by 3

[tex]p_{efgh}=20\ cm[/tex]

[tex]p_{abcd}=30\ cm\\\\p_{efgh}=20\ cm[/tex]