Sadi wanted to compare the fractions 2 3 and 5 9 using common denominators. His work is shown below. The common denominator is 9. Two-thirds times one-third = two-ninths. Two-ninths less-than five-ninths. So, two-thirds is less-than five-ninths. What errors did Sadi make? Check all that apply. The common denominator is 6, not 9. He should have multiplied by, not . He should have gotten a common numerator, not a common denominator. The fraction is greater than , not less than

n= 0.0000 - 0.3750 i

n= 0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

ye question kah se mil apko which std you are ??

dekho apne ye question m kuch to wrong show kiya hai plz do correct this is incorrect sis

the answer is 0.071

good luck! : d

He should have multiplied by [tex]\frac{3}{3}[/tex] and not [tex]\frac{1}{3}[/tex]

The fraction is greater than

Step-by-step explanation:

Given

[tex]\frac{2}{3}\ \&\ \frac{5}{9}[/tex]

Sadi's steps are:

The common denominator is 9.

[tex]\frac{2}{3} * \frac{1}{3} = \frac{2}{9}[/tex]

[tex]\frac{2}{9} < \frac{5}{9}[/tex]

So:

[tex]\frac{2}{3} < \frac{5}{9}[/tex]

Required

Sadi's error

Her first error is that: he should have multiplied by [tex]\frac{3}{3}[/tex] and not [tex]\frac{1}{3}[/tex]

This is so because, whatever factor is multiplied to the numerator has to be multiplied to the denominator, as well.

So, we have:

[tex]\frac{2}{3} * \frac{3}{3} = \frac{6}{9}[/tex]

By comparison:

[tex]\frac{6}{9} \frac{5}{9}[/tex]

So, his second error is that: the fraction is greater than