Sam has $0.85 in nickels( 0.05) and dimes (0.10) she has 2 more nickels than dimes. how many nickels

Sam has $0.85 in nickels( 0.05) and dimes (0.10) she has 2 more nickels than dimes. how many nickels and dimes does she have?

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  1. Option D

    There are 15 dimes and 5 nickels

    Solution:

    Let "d" be the number of dimes

    Let "n" be the number of nickels

    We know that,

    Value of 1 dime = $ 0.10

    Value of 1 nickel = $ 0.05

    There are three times more dimes than nickels

    Therefore,

    Number of dimes = 3(number of nickels)

    d = 3n ---------- eqn 1

    The total value is $ 1.75

    Therefore, we frame a equation as:

    Number of dimes x Value of 1 dime + number of nickels x Value of 1 nickel = 1.75

    [tex]d \times 0.10 + n \times 0.05 = 1.75[/tex]

    0.10d + 0.05n = 1.75 -------- eqn 2

    Substitute eqn 1 in eqn 2

    0.10(3n) + 0.05n = 1.75

    0.3n + 0.05n = 1.75

    0.35n = 1.75

    n = 5

    Substitute n = 5 in eqn 1

    d = 5(3)

    d = 15

    Thus there are 15 dimes and 5 nickels

  2. There are 9 nickels and 63 dimes.

    Step-by-step explanation:

    Let x be the number of nickels. There are 7 times as many dimes as nickels, so there are 7x dimes.

    Amount in dimes [tex]=7x\cdot 10=70x[/tex] cents

    Amount in nickels [tex]=x\cdot 5=5x[/tex] cents

    The value of dimes is $5.85 more than the value of the nickels, so

    [tex]70x-5x=585[/tex]

    Solve this equation

    [tex]70x-5x=585\\ \\65x=585\\ \\x=\dfrac{585}{65}\\ \\x=9[/tex]

    There are 9 nickels and 63 dimes.

  3. either 161 and 60 or 149 and 72

    Step-by-step explanation:

    either par adds up to 221 and they dont specify which number is for which

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