# Solve the equation for x, where x is a real number: -3x^2 + 4x – 5 = 0

Solve the equation for x, where x is a real number: -3x^2 + 4x - 5 = 0

## This Post Has 10 Comments

1. woodfordmaliky says:

The equation has no real solutions. (There are no x-intercepts.)

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The complex solutions are x = 0.625 ±i√1.359375
$Solve the equation for x, where x is a real number: -4x^2 + 5x - 7 = 0$

2. austinmontgomep7foxp says:

The trestle meets ground level at 0.9 units and 9.1 units

Step-by-step explanation:

∵ -x² + 10x - 8 = 0 ⇒ × (-1)

∴ x² - 10x + 8 = 0

∵ 10x/2 = 5x ⇒ (x) × (5) ⇒ square x is x² and square 5 is 25

By using completing square form

∴ (x² - 10x + 25) - 25 + 8 = 0

∴ (x - 5)² - 17 = 0

∴ (x - 5)² = 17 ⇒ take square root for both sides

∴ x - 5 = -√17 ⇒ x = -√17 + 5 = 0.9

∴ x - 5 = √17 ⇒ x = √17 + 5 = 9.1

∴ The trestle meets ground level at x = 0.9 and x = 9.1

3. andybiersack154 says:

The equation has no real solutions. (There are no x-intercepts.)

_____
The complex solutions are x = 0.15 ±i√0.1755.
$Solve the equation for x, where x is a real number: -10x^2 + 3x - 2 = 0$

4. tvrgrvJfbhh3881 says:

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √((7)^2 - 4(-2)(-5)) ] / ( 2(-2) )
x = [-7 ± √(49 - (40) ) ] / ( -4 )
x = [-7 ± √(9) ] / ( -4)
x = [-7 ± 3 ] / ( -4 )
x = 7/4 ± -3/4
The answers are 7/4 + 3/4 = 5/2 and 1.

5. ajanchondo2004 says:

The equation has no real solutions. (The graph has no x-intercepts.)

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The complex solutions are x = 0.4 ±i√0.44.
$Solve the equation for x, where x is a real number: -5x^2 + 4x - 3 = 0$

6. zionAboss says:

First you must know this.
${ax}^{2} + bx + c = 0$
Then, you will know that a=-2 b=7 c=-5.
$x = \frac{ \: - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$
$x = \frac{ \: - 7 + - \sqrt{ {7}^{2} - 4( - 2)( - 5) } }{2 \times - 2}$
You will then get two values for x.
$x = 1 \: and \: x = 2.5$
there you go! That's the answer.

7. HUNIXX5647 says:

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -4 ± √((4)^2 - 4(-3)(-5)) ] / ( 2(-3) )
x = [-4 ± √(16 - (60) ) ] / ( -6 )
x = [-4 ± √(-44) ] / ( -6)
Since √-44 is nonreal, the answer to this question is that there are no real solutions.

8. dijonmckenzie3 says:

To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
x = [-5 ± √(25 - (132) ) ] / ( -22 )
x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.

9. Naysa150724 says:

More analytically, we can apply the quadratic formula to find the solutions. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -3 ± √((3)^2 - 4(-10)(-2)) ] / ( 2(-10) )
x = [-3 ± √(9 - (80) ) ] / ( -20 )
x = [-3 ± √(-71) ] / ( -20)
Since √-71 is a nonreal number, there are no real solutions to this equation.

10. jackkie10 says:

$Solve the equation for θ, where 0 ≤ θ ≤ 2π.$