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  1. The answer is b i’m sure
    [tex]Given t is a transversal crossing parallel line m and n, m a. 60° b. 160° c. 100° d. 40° e. 140°[/tex]

  2. Log₅ 240-log₅75-log₅ 80=
    log₅ (240/75)-log₅ 80=                      (log_a b- log_a c=log_a (b/c) )
    :log₅3.2 - log₅80=                            
    log₅(3.2/80)=                                    (log_a b- log_a c=log_a (b/c) )  
    log₅0.04=
    log₅ 4/100=
    log₅ 1/25=
    log₅ 1 - log₅ 25=                                (log_a 1=0)
    0-log₅25=
    -log₅25=
    -log₅5²=x    ⇔ x=-2                            (log_a a^n=n)

    log₅ 240-log₅75-log₅ 80=-2

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