State if each set of three numbers can be the lengths of the sides of a triangle.

[tex]State if each set of three numbers can be the lengths of the sides of a triangle.[/tex]

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State if each set of three numbers can be the lengths of the sides of a triangle.

[tex]State if each set of three numbers can be the lengths of the sides of a triangle.[/tex]

To find if three number are a triangle, the formula is A^2 + B^2 = C^2. This means that when you square the lowest two terms they need to add to the square of the third number.

12^2 = 144

13^2 = 169

144 + 169 = 313

26^2 = 676

Since 313 does not equal 676 these numbers cant be the sides of a triangle.

No. It's no because if you do the correct math, you can see when you add the first side, 13 and 12, you get 25. 25 is < 26. All sides have to have a correct amount to be a triangle.

13+12>26

25>26 NO

12+26>13

38>13 YES

13+26>12

39>12 YES

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When you know 3 triangle sides: the longest side must be less than the sum of the other 2 sides.6) 5, 2, 9since 9 > (5 + 2) no triangle can be formed7) 3, 13, 21since 21 > (3 + 13) no triangle can be formed8) 11, 9 , 12since 12 < (11 + 9) a triangle will be formed9) 2, 3, 77 is greater than (3+2) no triangle can be formed10) 8, 11, 1212 < (8+11) a triangle will be formedsource:

Step-by-step explanation:

Imagine lying out 2 sticks with lengths 9 and 12

on the ground. The maximum length you can

get is by putting them in a straight line. (9 + 12 = 21)

However, 21 is less than 24, which is

supposed to be the 3rd side of the triangle.

Hence the set 9, 12, 24 cannot form a triangle.